Anyone help??? Thank you need it in 3 min

Mathematics

2 answers:

den301095 [7]3 years ago

7 0

Answer:

$40.352

Step-by-step explanation:

ale4655 [162]3 years ago

6 0

Answer:

666 ni\gdre

Step-by-step explanation

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There are 6 black scarves, 2 red scarves, and 2 white scarves in a drawer. In the dark, Angela pulls a scarf out of the drawer.

Elenna [48]

There is a 20 percent chance Angela will pull a red scarf, 60 percent chance she will pull a black scarf and 20 percent chance she will pull a white scarf. So if she pulls a red scarf then there will be a 18 percent chance she will pull a white scarf after.
I Hope this helps!

6 0

3 years ago

Read 2 more answers

Can someone please help

Vsevolod [243]

It may be convenient here to write the equation of the line as

... ∆y(x -x0) -∆x(y -y0) = 0

where (x0, y0) is a point on the line, and (∆x, ∆y) is the difference between two points on the line.

Using the first two points, we have

... (∆x, ∆y) = (-9, 10) - (-15, 5) = (6, 5)

So, the equation of the line is

... 5(x +9) -6(y -10) = 0 . . . . . . using the point (x0, y0) = (-9, 10)

... 5x -6y = -105 . . . . . . . . . . . simplify to standard form

Now, dividing by the constant on the right, we can put this into intercept form

... x/(-21) +y/(17.5) = 1

This tells us the y-intercept is (0, 17.5) and the x-intercept is (-21, 0).

_____

You can work directly with the values in the table. The y-value increases by 5 from one line to another, while the x-value increases by 6. Thus, to make the y-value decrease by 5 from the first point, we need to decrease that point's x-value by 6 to -21. That is, the x-intercept is (-21, 0).

Similarly, the x-value need to increase by only 3 from the last point. That amounts to half of the usual increase of 6. Thus the y-intercept will be the last point plus have the usual y-increase of 5, or 15+2.5 = 17.5. That is, the y-intercept is (0, 17.5).

5 0

3 years ago

Use ΔABC to find the value of tan b

Nezavi [6.7K]

Answer:

4.4444

Step-by-step explanation:

$\tan B = \dfrac{opp}{adj}$