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3 years ago

14

18 divided by 1919, how did you get your answer? Show your work!

1 answer:

GaryK [48]3 years ago

4 0

Answer:0.00937988535

Did you put them backwards or is that actually the question?

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Solve for r. k=3r-7s

const2013 [10]

R=7s/3+k/3

Hope this helps!

5 0

2 years ago

To one-one functions g and h are defined as follows.

Andreyy89

Answer:

9
(x-8)/3
-1

Step-by-step explanation:

The inverse function for a set of ordered pairs can be found by swapping the x- and y-coordinates in each pair.

$g^{-1}(-1)=9\qquad\text{from the $g(x)$ ordered pair $(9, -1)$}$

__

The inverse of a function expressed algebraically can be found by swapping the x- and y-variables and solving for y.

$h^{-1}(x)\qquad\text{is found from }x=h(y)\\\\x=3y+8\\x-8=3y\\\\y=\dfrac{x-8}{3}\\\\\boxed{h^{-1}(x)=\dfrac{x-8}{3}}$

A function of its own inverse returns the original value:

$\boxed{\left(h\circ h^{-1}\right)(-1)=-1}$

6 0

2 years ago

Find the percent increase. Round to the nearest percent. From 13 friends to 16 friends

larisa86 [58]

The percentage increase; you'll need to take the new value and subtract it by the old value.

16 - 13 = 3

Next, you'll divide 3 by the original value.

3 ÷ 13 = 0.23

And multiply by 100

The percentage increase of friends is 23%

8 0

3 years ago

Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

2 years ago

Help me find the answer

solmaris [256]

I possibly think it is c that is what I got

8 0

2 years ago