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Butoxors [25]
3 years ago
8

All students chose a sport 40% chose Football, 37.5% chose baseball 18 chose other sports. How many students particpated?

Mathematics
2 answers:
Arlecino [84]3 years ago
7 0
The answer would be 80 students
sasho [114]3 years ago
3 0
What i do is i take the original number of students and multiply by 40% then i will add it to 18. Then i will do the same thing to 37.5%. 
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Sistema de ecuaciones.5x+2y=-152x-2y=-6
Zolol [24]

Tnemos el sisema de ecuaciones:

\begin{gathered} 5x+2y=-15 \\ 2x-2y=-6 \end{gathered}

Podemos resolverlo por eliminación sumando ambas ecuaciones y eliminando y. Asi podemos resolver para x:

\begin{gathered} (5x+2y)+(2x-2y)=(-15)+(-6) \\ 7x+0y=-21 \\ x=-\frac{21}{7} \\ x=-3 \end{gathered}

Ahora podemos resolver para y con cualquiera de las dos ecuaciones:

\begin{gathered} 2x-2y=-6 \\ 2\cdot(-3)-2y=-6 \\ -6-2y=-6 \\ -2y=-6+6 \\ -2y=0 \\ y=0 \end{gathered}

Respuesta: x=-3, y=0

7 0
1 year ago
Please help its kind of easy but i really need it
hram777 [196]

Answer:

it a poster what do you need help with

Step-by-step explanation:

this is the exact poster or flyer

Download pdf
4 0
3 years ago
debt A sum of $80000 cam Rs 31000 due in 3 years and a debt of Rs 2000 due in 4 years is to be Paid by single payments 4 years h
Gennadij [26K]

Answer:

551.25

im sorry if its wrong

5 0
2 years ago
7n +9 = -1+6(n+4)<br>can someone walk me through this please?​
Ira Lisetskai [31]

Answer:

n = 14

Step-by-step explanation:

7n +9 = -1+6(n+4)

Distribute

7n+9 = -1 +6n+24

Combine like terms

7n +9 = 6n +23

Subtract 6n from each side

7n -6n+9 = 6n-6n +23

n+9 = 23

Subtract 9 from each side

n+9-9=23-9

n = 14

6 0
3 years ago
What is the total perimeter of the pitch and seating area?
vazorg [7]
Answer:
The total Perimeter of the pitch and seating area is 179.83 m an the Total Area is 1394 m²
Step-by-step explanation:
Figure is attached with required naming.
Length of the Rectangle 1 = 40 m
width of the Rectangle 2 = 2000 cm = 20 m
radius of semi circle 2 =
radius of semi circle 3 =
length of the rectangle 4 = 25 m
width of the rectangle 4 = 800 cm = 8 m
length of the rectangle 5 = 10 m
width of the rectangle 5 = 800 cm = 8 m
Total Perimeter of the pitch and seating area
= length of rectangle 1 + circumference of semi circle 2 + circumference of semi circle 3 + length of rectangle 4 + 2 × width of rectangle 4 + length of rectangle 5 + 2 × width of the rectangle 5 + (length of rectangle 1 - length of rectangle 4 - length of he rectangle 5)
= 40 + π(10) + π(10) + 25 + 2 × 8 + 10 + 2 × 8 + ( 45 - 25 -10 )
= 40 + π(10) + π(10) + 25 + 16 + 10 + 16 + 10
= 117 + 20π
= 179.83 m (approx.)
Total area of the pitch and seating area
= Area of the Rectangle 1 + Area of semi circle 2 + area of semi circle 3 + area of rectangle 4 + area of rectangle 5
= 40 × 20 + π(10)² + 25 × 8 + 10 × 8
= 800 + 100π + 200 + 80
= 1080 + 314
= 1394 m²
Therefore, The total Perimeter of the pitch and seating area is 179.83 m an the Total Area is 1394 m²
5 0
3 years ago
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