Answer:
Step-by-step explanation:
it is given that Square contains a chord of of the circle equal to the radius thus from diagram
If Chord is equal to radius then triangle PQR is an equilateral Triangle
Thus
In triangle PQO applying Pythagoras theorem
Thus length of Side of square
Area of square
Area of Circle
Ratio of square to the circle
Answer:
Step-by-step explanation:
The picture is below of how to separate this into 2 different regions, which you have to because it's not continuous over the whole function. It "breaks" at x = 2. So the way to separate this is to take the integral from x = 0 to x = 2 and then add it to the integral for x = 2 to x = 3. In order to integrate each one of those "parts" of that absolute value function we have to determine the equation for each line that makes up that part.
For the integral from [0, 2], the equation of the line is -3x + 6;
For the integral from [2, 3], the equation of the line is 3x - 6.
We integrate then:
and
sorry for the odd representation; that's as good as it gets here!
Using the First Fundamental Theorem of Calculus, we get:
(6 - 0) + (-4.5 - (-6)) = 6 + 1.5 = 7.5
Answer:
b=0.00906m
Step-by-step explanation:
Hello! To solve this exercise we must remember that the area of any triangle is given by the following equation
where
A=area=32.5m^2
h=altitude=7172m
b=base
Now what we should do take the equation for the area of a rectangle and leave the base alone, remember that what we do on one side of the equation we must do on the other side to preserve equality
solving
