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3 years ago

The volume of a cylinder is the 48 ft the area of the base is 12 ft. what is the height of the cylinder

Mathematics

1 answer:

monitta3 years ago

8 0

4 ft is the height of the cylinder

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Compare these two functions. Which<br> has the greater rate of change?<br> y= -6x + 7

Diano4ka-milaya [45]

Answer:

y = -6x + 7 has greater rate of change

Step-by-step explanation:

for the first one, the rate of change is -6x and for the second one, the rate of change is -5x so the rate of change for y = -6x + 7 is greater.

Use the formula y2 - y1 / x2 - x1 to find the slop for the second equation. the second equation is y = -5x

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MrRissso [65]

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Step-by-step explanation:

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3 years ago

State the domain restriction(s) in interval notation of \displaystyle f\left(g\left(x\right)\right)f(g(x)) given: \displaystyle

DENIUS [597]

Answer:

The interval notation for the domain is $[\frac{23}{3},\infty ]$ .

Step-by-step explanation:

Consider the provided information.

It is given that $\:f\left(x\right)=\sqrt{3x-2},\:\text{ and }\:g\left(x\right)=x-7$

We need to find the value of $f\left(g\left(x\right)\right)$ .

Put the value of g(x) in $f\left(g\left(x\right)\right)$ .

$f\left(g\left(x\right)\right)=f(x-7)$ ....(1)

Now, put x=x-7 in $\:f\left(x\right)=\sqrt{3x-2}$

$\:f\left(x-7\right)= \sqrt{3(x-7)-2}$

$\:f\left(x-7\right)= \sqrt{3x-21-2}$

$\:f\left(x-7\right)= \sqrt{3x-23}$

From equation 1.

$f\left(g\left(x\right)\right)=\:f\left(x-7\right)= \sqrt{3x-23}$

The domain of the function is the set of input values for which a function is defined.

Here, the value of $3x-23$ should be greater or equal to 0 as the square root of a negative number is not real.

Domain= $3x-23\geq0$

$x\geq\frac{23}{3}$

The value of x is all real number greater than $\frac{23}{3}$ .

Hence, the interval notation for the domain is $[\frac{23}{3},\infty ]$ .

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3 years ago