Answer:
.
(Expand to obtain an equivalent expression for the sphere:
)
Step-by-step explanation:
Apply the Pythagorean Theorem to find the distance between these two endpoints:
.
Since the two endpoints form a diameter of the sphere, the distance between them would be equal to the diameter of the sphere. The radius of a sphere is one-half of its diameter. In this case, that would be equal to:
.
In a sphere, the midpoint of every diameter would be the center of the sphere. Each component of the midpoint of a segment (such as the diameter in this question) is equal to the arithmetic mean of that component of the two endpoints. In other words, the midpoint of a segment between
and
would be:
.
In this case, the midpoint of the diameter, which is the same as the center of the sphere, would be at:
.
The equation for a sphere of radius
and center
would be:
.
In this case, the equation would be:
.
Simplify to obtain:
.
Expand the squares and simplify to obtain:
.
Answer:
Rational
Step-by-step explanation:
Rational numbers can be reduced to a fraction
Irrational numbers cannot be reduced to a fraction
Whole numbers are positive numbers that are not decimal or fraction
Integers are all numbers that are not decimal or fraction
Answer:
1100 field-side tickets and 4500 end-zone tickets.
Step-by-step explanation:
Let x represent number of field side tickets and y represent number of end-zone tickets.
We have been given that the total number of people at a football game was 5600. We can represent this information in an equation as:

We are also told that Field-side tickets were 40 dollars and end-zone tickets were 20 dollars.
Cost of x field side tickets would be
and cost of y end-zone tickets would be
.
The total amount of money received for the tickets was $134000. We can represent this information in an equation as:

Upon substituting equation (1) in equation (2), we will get:







Therefore, 1100 field side tickets were sold.
Upon substituting
in equation (1), we will get:


Therefore, 4500 end-zone tickets were sold.
You use the Pythagorean theorem which is a^2+b^2=c^2
So....
.8^2+.6^2=c^2
.64+.36=c^2
1=c^2
1=c becaaue the square root of one is one