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Oksanka [162]
3 years ago
12

If you ungroup 5,000 from 2,896 how do you explain the place value of 49910 to 5,000

Mathematics
1 answer:
katovenus [111]3 years ago
3 0
You get all of the numbers and turn them too zeros except the first one
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Answer:

1335$ because 8900*15/100=1335

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Solve for B - PLEASE HELP IMMA DIE
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First, you would have to add d to both sides to get rid of it
x+d=ab+c/b
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x+d(b)=ab+c
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If the average daily high temperature for the week was 28C, find the missing temperature from the following list: 25C, 26C, 31C,
DiKsa [7]
I believe the answer would be 27C.
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Tara is saving for an overseas trip. Her taxable income is usually about $20000. She estimates that she will need $5000 for the
wolverine [178]

An income is taxable is such income falls into a category where a proportion of the income is removed, as tax. To have an extra $5000 after tax, Tara must save $6173.

Given that:

Earnings = \$20000 --- normal earnings

Amount = \$5000 ---- the amount needed

From the complete question, the tax rate for earnings between $18201 and $37000 is 19%.

Let the additional amount be x.

So, the equation that calculates the amount needed (after tax) is:

x(1 - 19\%) = 5000

Express as decimal

x(1 - 0.19) = 5000

x(0.81) = 5000

Make x the subject

x = \frac{5000}{0.81}

x = \$6173

Hence, she needs to make an extra of $6173 to save $5000

Read more about taxable income at:

brainly.com/question/17347618

4 0
2 years ago
Brandon is on one side of a river that is 50 m wide and wants to reach a point 300 m downstream on the opposite side as quickly
AlexFokin [52]
Let P be Brandon's starting point and Q be the point directly across the river from P. 
<span>Now let R be the point where Brandon swims to on the opposite shore, and let </span>
<span>QR = x. Then he will swim a distance of sqrt(50^2 + x^2) meters and then run </span>
<span>a distance of (300 - x) meters. Since time = distance/speed, the time of travel T is </span>

<span>T = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x). Now differentiate with respect to x: </span>

<span>dT/dx = (1/4)*(2500 + x^2)^(-1/2) *(2x) - (1/6). Now to find the critical points set </span>
<span>dT/dx = 0, which will be the case when </span>

<span>(x/2) / sqrt(2500 + x^2) = 1/6 ----> </span>

<span>3x = sqrt(2500 + x^2) ----> </span>

<span>9x^2 = 2500 + x^2 ----> 8x^2 = 2500 ---> x^2 = 625/2 ---> x = (25/2)*sqrt(2) m, </span>

<span>which is about 17.7 m downstream from Q. </span>

<span>Now d/dx(dT/dx) = 1250/(2500 + x^2) > 0 for x = 17.7, so by the second derivative </span>
<span>test the time of travel, T, is minimized at x = (25/2)*sqrt(2) m. So to find the </span>
<span>minimum travel time just plug this value of x into to equation for T: </span>

<span>T(x) = (1/2)*sqrt(2500 + x^2) + (1/6)*(300 - x) ----> </span>

<span>T((25/2)*sqrt(2)) = (1/2)*(sqrt(2500 + (625/2)) + (1/6)*(300 - (25/2)*sqrt(2)) = 73.57 s.</span><span>
</span><span>
</span><span>
</span><span>
</span><span>mind blown</span>
8 0
3 years ago
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