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3 years ago

Anyone good at math

Mathematics

2 answers:

dalvyx [7]3 years ago

3 0

Answer:

Step-by-step explanation:

Lorico [155]3 years ago

3 0

Answer:

Step-by-step explanation:

10/50 = k/30

Cross multiply

300=50k

Divide by 50

K= 6

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What is the equation of the line that passes through (0, -2) and has a slope of 0?

11Alexandr11 [23.1K]

Answer:

y = -2

Step-by-step explanation:

The horizontal line through this point has a slop of 0

8 0

3 years ago

Need help on this asap!! Also Thank you in advance!!

sattari [20]

Answer:

31.96 centimeter is the answer

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3 years ago

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Find an equation of the plane orthogonal to the line

jolli1 [7]

The given line is orthogonal to the plane you want to find, so the tangent vector of this line can be used as the normal vector for the plane.

The tangent vector for the line is

d/dt (⟨0, 9, 6⟩ + ⟨7, -7, -6⟩t ) = ⟨7, -7, -6⟩

Then the plane that passes through the origin with this as its normal vector has equation

⟨x, y, z⟩ • ⟨7, -7, -6⟩ = 0

We want the plane to pass through the point (9, 6, 0), so we just translate every vector pointing to the plane itself by adding ⟨9, 6, 0⟩,

(⟨x, y, z⟩ - ⟨9, 6, 0⟩) • ⟨7, -7, -6⟩ = 0

Simplifying this expression and writing it standard form gives

⟨x - 9, y - 6, z⟩ • ⟨7, -7, -6⟩ = 0

7 (x - 9) - 7 (y - 6) - 6z = 0

7x - 63 - 7y + 42 - 6z = 0

7x - 7y - 6z = 21

so that

a = 7, b = -7, c = -6, and d = 21

4 0

3 years ago

What is the slope of a line that is perpendicular to the line whose equation is 8y−5x=11?

ElenaW [278]

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Answer:

-8/5

Step-by-step explanation:

When you solve for y, the slope of the line is the x-coefficient. For the given line, that is ...

8y = 5x +11 . . . . . add 5x

y = 5/8x +11/8 . . . . divide by 8

The given line has a slope of 5/8. The perpendicular line will have a slope that is the opposite of the reciprocal of this:

-1/(5/8) = -8/5 . . . . slope of perpendicular line

4 0

3 years ago

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Write the equation of the circle with center (-4, 8) and passes through the point (-2, -1)

anzhelika [568]

Answer:

$(x+4)^2+(y-8)^2=85$

Step-by-step explanation:

The standard equation for a circle is given by:

$(x-h)^2+(y-k)^2=r^2$

Where (h, k) is the center and r is the radius.

We know that the center is (-4, 8). So, substitute -4 for h and 8 for k:

$(x-(-4))^2+(y-8)^2=r^2\\$

Simplify:

$(x+4)^2+(y-8)^2=r^2$

Now, we will need to find r.

We know that it passes through the point (-2, -1). So, we can substitute -2 for x and -1 for y and solve for r. So:

$(-2+4)^2+(-1-8)^2=r^2$

Evaluate:

$(2)^2+(-9)^2=r^2$

Square:

$4+81=r^2$

Add:

$r^2=85$

So, r squared is 85.

We don’t actually have to solve for r itself, since we will have to square it anyways.

So, we have:

$(x+4)^2+(y-8)^2=r^2$

Substituting 85 for r squared, we get:

$(x+4)^2+(y-8)^2=85$

And we have our equation.

8 0

3 years ago