Answer:
3.89 m/s
Explanation:
If we want an average velocity for the whole race of 3.81 m/s in a 1600 m course, the course it must be completed in:
.
So, the runner already run for 5 minutes and 25 seconds, this is
.
For finishing the course, the runner has
.
Now, the distance that the runner has to cover in this time its:
![1600 \ m - 1230 \ m = 370 \ m](https://tex.z-dn.net/?f=1600%20%5C%20m%20-%201230%20%5C%20m%20%3D%20370%20%5C%20m)
Finally, the runner average velocity for the remainder will be:
![V= \frac{distance \ left}{time \ left} = \frac{370 \ m}{95 \ s} = 3.89 \ \frac{m}{s}](https://tex.z-dn.net/?f=%20V%3D%20%5Cfrac%7Bdistance%20%5C%20left%7D%7Btime%20%5C%20left%7D%20%3D%20%5Cfrac%7B370%20%5C%20m%7D%7B95%20%5C%20s%7D%20%3D%203.89%20%5C%20%5Cfrac%7Bm%7D%7Bs%7D)
Answer:
The correct answer is B. 0.64 m/s²
Explanation:
According to the Newton's Second law of motion acceleration of an object by a net force is directly proportional to the magnitude of the net force, in the same direction as the net force.
Mathematically,
F ∝ a
F = ma
Given data:
Force = F = 35 N
Mass = m = 55 kg
acceleration = a = ?
F = ma
a = F/m
a = 35/55
a = 0.64 m/s²
Answer:
2 m/s^2
Explanation:
from the question
v=15 m/s
t=7.5
a=?
from the first equation of motion
v=u+at
where,
v=final velocity
u=initial velocity
a=acceleration
t=time
from the question (u) will be zero because the body started at rest
v=u+at
15=(0)+a×7.5
15=7.5a
a=15/7.5
a=2 m/s^2
Https://www.lsop.colostate.edu/wp-content/uploads/sites/6/2014/10/HurricanesGoCounterclockwise.pdf
Answer:
so nothing can fly through it
Explanation:
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