1. neutral particles (neutrons) are in the nucleus
2. nucleus is in the nucleus
3. electron cloud is in the electron cloud
4. positively charged particles (protons) are in the nucleus
5. negatively charged particles (electrons) are in the electron cloud
Answer:
Thermal and internal energy is equal to the sum total kinetic energy possessed by the the molecules whereas the heat energy is the transfer of thermal energy from high temperature to low temperature.
HOPE THIS HELPED!!!!
<span>By being poor, you can become better because you can cultivate a better personality. Things, items, phones distract you & if you're poor, then you're more inclined to be productive & have more in a sense.
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
</span>
<span>The answer is 6 kg the mass of the second
object. By using Inversely proportional formula it means that (14 kg) (3 m/s</span>²<span>)
= M (7 m/s</span>²<span>). Where M is the mass of the second object. For the
Newton’s second law of motion formula which is: Force = mass x acceleration, we
have:</span>
<span>F = (14 kg) (3 m/s</span>²<span>) = 42 N</span>
Therefore:
<span>42 N = M (7 m/s</span>²)
<span>M = (42 N) / (7 m/s</span>²<span>)</span>
M = 6 kg mass of the second object
(a) Equating centripetal force to friction force, one finds the relation
v² = kar
for car speed v, coefficient of friction k, radius of curvature r, and downward acceleration a.
There is already downward acceleration due to gravity. The additional accceleration due to the wing is
a = F/m = 10600 N/(805 kg) ≈ 13.1677 m/s²
We presume this is added to the 9.80 m/s² gravity provides, so the coefficient of friction is
k = v²/(ar) = (54 m/s)²/((13.1677 m/s² +9.80 m/s²)·(155 m))
k ≈ 0.8191
(b) The maximum speed is proportional to the square root of the downward acceleration. Changing that by a factor of 9.80/(9.80+13.17) changes the maximum speed by the square root of this factor.
max speed with no wing effect = (54 m/s)√(9.8/22.97) ≈ 35.27 m/s
