Question

When you hit a .27 kg volleyball the contact time is 50 ms and the average force is 125 N. If you serve the volleyball (from rest) sending it up at 30 degrees above the horizontal, what is the
A) vertical component of the momentum of the volleyball in kgm/s?
B) horizontal component of the momentum of the volleyball in kgm/s?

Answer 1

(A) P(v) = 0.135v

(B) P(h) = 0.234v

Explanation:

Given-

Mass of the ball, m = 0.27kg

Force, F = 125N

angle of projection, θ = 30°

Let v be the velocity of the ball.

A) vertical component of the momentum of the volleyball

We know,

P(vertical) = mvsinθ

P(V) = 0.27 X v X sin 30°

P(V) = 0.27 X v X 0.5

P(V) = 0.135v

B) horizontal component of the momentum of the volleyball

We know,

P(Horizontal) = mvcosθ

P(h) = 0.27 X v X cos 30°

P(h) = 0.27 X v X 0.866

P(h) = 0.234v