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Juliette [100K]
3 years ago
13

X-4y= -2 3x-y=5 in y form

Mathematics
1 answer:
Mamont248 [21]3 years ago
7 0
X-4y=-2
-x. -x
4y=-2-x
4y=x-(-2)
/4. /4
Y=4x+2/4



3x-y=5
-3x. -3x
-y=5-3x
-y=-3x+5
/-1. /-1
Y=3x-5
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La finca de Federico tiene tiene un área de 576 m2, En ella ha sembrado naranja y café, 3/8 de la finca están sembrados de naran
Vanyuwa [196]

Answer:

El área de la finca que está sembrada por café es 360 m².

Step-by-step explanation:

La finca de Federico tiene tiene un área de 576 m². \frac{3}{8} de la finca están sembrados de naranjas. Entonces, el área de la finca que está sembrada por naranjas se calcula mediante:

576 m²* \frac{3}{8} = 216 m²

Sabiendo que el resto de la finca esta sembrada de café, esta área se calcula mediante la diferencia del área total de la finca y el área sembrada por naranjas:

576 m² - 216 m²= 360 m²

<u><em>El área de la finca que está sembrada por café es 360 m².</em></u>

6 0
3 years ago
What is 270 divided by 6
morpeh [17]
Your answer would be 45,because 6 times 45 equals to 470,and thats how many times 6 can go into 470,exactly 45 times

8 0
3 years ago
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Inputs are represented by the variable x .<br><br><br> True or False
NNADVOKAT [17]

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true

Step-by-step explanation:

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2 years ago
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An n × n matrix B has characteristic polynomial p(λ) = −λ(λ − 3) 3 (λ − 2) 2 (λ + 1). Which of the following statements is false
asambeis [7]

Answer:

Only d) is false.

Step-by-step explanation:

Let p=p(\lambda)=\lambda(\lambda-3)^3 (\lambda-2)^2 (\lambda+1) be the characteristic polynomial of B.

a) We use the rank-nullity theorem. First, note that 0 is an eigenvalue of algebraic multiplicity 1. The null space of B is equal to the eigenspace generated by 0. The dimension of this space is the geometric multiplicity of 0, which can't exceed the algebraic multiplicity. Then Nul(B)≤1. It can't happen that Nul(B)=0, because eigenspaces have positive dimension, therfore Nul(B)=1 and by the rank-nullity theorem, rank(B)=7-nul(B)=6 (B has size 7, see part e)

b) Remember that p(\lambda)=\det(B-\lambda I). 0 is a root of p, so we have that p(0)=\det(B-0 I)=\det B=0.

c) The matrix T must be a nxn matrix so that the product BTB is well defined. Therefore det(T) is defined and by part c) we have that det(BTB)=det(B)det(T)det(B)=0.

d) det(B)=0 by part c) so B is not invertible.

e) The degree of the characteristic polynomial p is equal to the size of the matrix B. Summing the multiplicities of each root, p has degree 7, therefore the size of B is n=7.      

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Which of the following expressions is equivalent to 3p^4
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