Answer:
g(x) = 4(x - 1)(x2 + 4)(x + 6)
= 4(x - 1)(x + 2)^2(x + 6)
The roots are:
1, -2, and -6
(x - 1), or 1, has a multiplicity of 4,
(x + 2), or -2, has a multiplicity of 2,
and (x + 6), or -6, has a multiplicity of 1
To determine whether or not they're real zeros, substitute them into the equation.
g(1) = 4(1 - 1)2(1 + 2)(1 + 6)
= 4(0)(3)^2(7)
= 0(9)(7)
= 0
g(-2) = 4(-2 - 1)(-2 + 2)^2(-2 + 6)
= 4(-3)(0)^2(4)
= (-12)(0)(4)
= 0
g(-6) = 4(-6 - 1)(-6 +2)^2(-6 + 6)
= 4(-7)(-4)^2(0)
= (-28)(16)(0)
= 0
Since all of the roots, when substituted into the equation equal 0, they're all real zeros.
(Sorry for this being so long..I hope it helped!)
Hello :
<span>y-intercepts when : y = 0 : x² +(0-2)² = 16
x² = 12....(1)
two </span>y-intercepts because the equation (1) has two solutions
It would be 60 feet because they are 60 feet apart for all the bases.
Yeah you right, it is the center of the given circle