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3 years ago

7

A painter has enough paint to cover 300 square feet of surface. Which square section of a wall is the largest she could cover wi

th this much paint? A. 16 ft by 16 ft B. 17 ft by 17 ft C. 18 ft by 18 ft D. 19 ft by19 ft

1 answer:

jeka943 years ago

4 0

1) 16 X 16= 256
2) 17 x 17 = 289
3) 18 x 18 = 324
4) 19 x 19 = 361
the answer is 2 because it's the largest number that is smaller than 300.

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The diagram represents 6x^2 - 7x + 2 with a factor of 2x - 1. What is the other factor of 6x^2 - 7x + 2?

Marizza181 [45]

Answer:

<h2>A. 3x - 2</h2>

Step-by-step explanation:

$\dfrac{6x^2}{2x}=3x,\ \dfrac{-3x}{-1}=3x\\\\\dfrac{-4x}{2x}=-2,\ \dfrac{2}{-1}=-2\\\\\underline{.\qquad|\ \ 2x\ |\ -1\ |}\\\underline{.\ 3x\ \ |\ 6x^2\ |-3x|}\\.\ -2|-4x|\ \ 2\ \ |$

$\text{Check:}\\\\(2x-1)(3x-2)=(2x)(3x)+(2x)(-2)+(-1)(3x)+(-1)(-2)\\\\=6x^2-4x-3x+2=6x^2-7x+2\qquad\text{CORRECT}$

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3 years ago

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Solve one and two tenths plus eight and one eighteenth

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47

Is this it?

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3 years ago

What is 5.27 in Tenths place

Aloiza [94]

5.3 would be round to the tenth place.

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3 years ago

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se quiere pintar una pared en forma de hexágono regular y se sabe que cada lado mide 3m y que su apotema es de 2,8m cual es el a

qwelly [4]

Answer:

El área total a pintar será:

$A_{tot}=25.2\: m^{2}$

Step-by-step explanation:

Sabiendo el apotema y la longitu de los lados, podemos encontrar el área de un triangulo. Recordemos que, si trazamos rectas del centro del hexágono a los vértices, se formaran 6 triángulos equiláteros.

El área de un triángulo es:

$A_{t1}=\frac{b*a}{2}$

b es la longitud de la base (b=3 m)

a es la apotema, osea la altura del triangulo (a = 2.8)

$A_{t1}=\frac{2.8*3}{2}$

$A_{t1}=4.2\: m^{2}$

Ahora, solo debemos mutiplicar ese valor por 6 para determianr el área total de la pared.

$A_{tot}=25.2\: m^{2}$

Espero te haya sido util!

5 0

3 years ago

ella [17]

Answer:

120

Step-by-step explanation:

We are given that the function for the number of students enrolled in a new course is $f(x) = 4^{x}-1$ .

It is asked to find the average increase in the number of students enrolled per hour between 2 to 4 hours.

We know that the average rate of change is given by,

$A = \frac{f(x)-f(a)}{x-a}$ ,

where f(x)-f(a) is the change in the function as the input value (x-a) changes.

Now, the number of students enrolled at 4 = f(4) = $f(x) = 4^{4}-1$ = 255 and the number of students enrolled at 2 = f(2) = $f(x) = 4^{2}-1$ = 15

So, the average increase $A=\frac{f(4)-f(2)}{4-2}$ = $A=\frac{255-15}{4-2}$ = $A=\frac{240}{2}$ = 120.

Hence, the average increase in the number of students enrolled is 120.

3 0

3 years ago