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Maru [420]
4 years ago
6

Please help me ٩( ᐛ )و

Mathematics
1 answer:
kondaur [170]4 years ago
3 0

Answer:

uhm i cant really see it

Step-by-step explanation:

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An acute angle θ is in a right triangle with cos θ = 9/10 . What is the value of sec θ?
xenn [34]

By definition

... sec(θ) = 1/cos(θ) . . . . trig identity

... sec(θ) = 1/(9/10) . . . . substitute the given value, then simplify to ...

... sec(θ) = 10/9

8 0
3 years ago
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John bought 15 cookies and ate 3 of them. What percentage did he eat?
DiKsa [7]
20% is the answer
Hope this helps
8 0
3 years ago
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The function g(n) = n2 - 6n + 16 represents a parabola.
stich3 [128]

Hi,

Part A:

g(n) = n^2 - 6n + 16 \\=(n^2-2*3*n+3^2+7)\\=(n-3)^2+7\\

Part B;

Vertex is (3,7)

As the coefficient of n² is positive , the vertex is a minimum.

Part C:

Axis of symmetry is n=3

5 0
3 years ago
two parallel lines are cut by a transversal as shown below. Suppose m<8=131. Find m<1 and m<3.
Olegator [25]

Answer:

m∠1 is 49° and m∠3 is 49°

Step-by-step explanation:

In the given figure

∵ There are 2 parallel lines

∵ A transversal cuts them

∴ ∠4 and ∠8 are corresponding angles

→ Corresponding angles are equal in measures

∴ m∠4 = m∠8

∵ m∠8 = 131°

∴ m∠4 = 131°

∵ ∠1 and ∠4 formed a pair of linear angle

∵ The sum of the measures of the linear angles is 180°

∴ m∠1 + m∠4 = 180°

→ Substitute ∠4 by 131°

∴ m∠1 + 131° = 180°

→ Subtract 131 from both sides

∵ m∠1 + 131 - 131 = 180 - 131

∴ m∠1 = 49°

∵ ∠1 and ∠3 are vertically opposite angles

∴ m∠1 = m∠3

∵ m∠1 = 49°

∴ m∠3 = 49°

4 0
3 years ago
Does 10p/2q = 5p/q<br> I think it is not equal but it doesn't seem right.
Rufina [12.5K]

Answer: \frac{10p}{2q}=\frac{5p}{q}  (TRUE)

Step-by-step explanation:

For this exercise it is important to remember that, by definition, fractions have the following form:

\frac{a}{b}

Where "a" is the numerator and "b" is the denominator.

The numerator and the denominator are Integers, but the denominator cannot be zero (b\neq 0)

In this case you have the following equation provided in the exercise:

\frac{10p}{2q}=\frac{5p}{q}

To find out if the left side of the equation is equal to the right side, it is necessary to simplify the fraction on the left.

Notice that the numerator and the denominator of the fraction on the left  can be both divided by 2. Then, you can simplify it.

So, you get;

\frac{5p}{q}=\frac{5p}{q}\ (TRUE)

6 0
4 years ago
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