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Travka [436]
3 years ago
12

In mrs. prosser's class there are 32 students. If 3 out of every 8 prefer to ride their bicycles to school, how many students in

the entire class like to ride their bicycles to school?
Mathematics
1 answer:
Molodets [167]3 years ago
8 0
First divide 32 by 8

32/8

=4

Then multiply the 4 by 3 to find out how many students in the class like to ride their bicycles to school

4x3

12 students is your answer
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Microsoft wanted to increase the average length of time consumers spend playing their games during a gaming session. They found
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Answer:

The answer is "Yes".

Step-by-step explanation:

In this question, the answer is "yes" because as the sample group of 50, it is now under the population size of 10 percent, and Often the random sample is less than 30. It doesn't require the standard deviation, and for each of the samples it was selected randomly, therefore randomization becomes achieved.

5 0
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Can anyone help me please
Nady [450]

Yo sup??

since WY is the perpendicular bisector we can say

3x-5=2x+3

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three children each ate 1/4 of a candy bar.Whitch expression shows how you would solve for the totalamount of candy bar that was
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3 years ago
Read 2 more answers
Tyler does squats and pushups. He wants to increase the number of each type of exercise by 20% by the end of the month. He curre
Semenov [28]

Answer:

Tyler currently does 40 squats

Step-by-step explanation:

Tyler does squats and pushups.

<u>Currently:</u>

Number of pushups = 25

Number of squats = x

Total number = 25 + x

<u>After increase:</u>

Number of pishups =25\cdot (1+0.2)=1.2\cdot 25=30

Number of squats =x\cdot (1+0.2)=1.2x

Total number =30+1.2x

If Tyler meets his goal, he will do a total of 13 more squats and pushups than he does now, thus

(30+1.2x)-(25+x)=13\\ \\30+1.2x-25-x=13\\ \\1.2x-x=13-30+25\\ \\0.2x=8\\ \\2x=80\\ \\x=40

6 0
3 years ago
Two athletic teams play a series of games; the first team to win 4 games is declared the overall winner. Suppose that one of the
kodGreya [7K]

Answer:

  • p=0.7103 (4-game series)
  • p=0.6480 (2-game series)

Step-by-step explanation:

Let X be the random variable equal the the first 4 straight wins. An overall win for the stronger team implies a negative binomial function with the parameters  n=4, p=0.6:

P(X=4)={{i-1}\choose {4-1}}0.6^40.4^{i-4},\  i=4,5,6,7

#We find probabilities for the different values of i:

P(X=4)={3\choose 3}0.6^4=0.1296\\\\P(X=5)={4\choose 3}0.6^40.4^1=0.2074\\\\P(X=6)={5\choose 3}0.6^40.4^2=0.2074\\\\P(X=4)={6\choose 3}0.6^40.4^3=0.1659

Hence, probability of the stronger team winning overall is:

=P(X=4)+P(X=5)+P(X=6)+P(X=7)\\\\=0.7103

#Define Y as the random variable for winning 2/3 games.:

P(Y=2)={1\choose 1}0.6^2=0.3600\\\\P(Y=3)={2\choose3}0.6^20.4=0.2880\\\\P(win)=0.2880+0.3600=0.6480

Hence, probability of the stronger team winning in 2 out 3 game series is 0.6480

The stronger team has a higher chance of winning in a 4-game series(0.7103>0.6480)

8 0
3 years ago
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