Answer:
The answer to the question is;
The number of papers expected to be handed in before receiving each possible grade at least once is 14.93.
Step-by-step explanation:
To solve the question , we note that it is a geometric distribution question which have equal probabilities and therefore is a form of Binomial distribution with Bernoulli trials, where we are conducting the trials till we have r successes
Since we have r = 6, we will have to find the expected value of the number of trials till the nth paper handed in receives a previously awarded grade.
We therefore have,
The Probability that out of six papers turned 5 are different scores is given by
P(Y=5) = p'= q⁵p = (1-p)⁵p = 3125/46656
Therefore p' = the probability of receiving different grades once then the expected value is given by
E(X) = 1/p' = 46656/3125 = 14.93.
Convert everything to pints and add them up.
1 quart is 2 pints
4 pints of OJ+1 pint of CJ+(2+4) pints of GA= 11 pints of fruit punch
<span>9,500,000 is the next number in the pattern. Each time you multiply the number on the left by 100 to get the number on the right.</span>
You do 9+3 which equals 12 then you multiply that by 4
Let's say "n" is a natural number. {1,2,3,4,..} To ensure we have an even number we will multiply "n" by 2. Two times any number will make an even number.
consecutive even numbers are like; 2, 4, 6, 8, 10 .. etc. Add +2 to the previous number to get the next consecutive.
1st even number = 2n
2nd even number = 2n + 2
3rd even number = 2n + 4
twice the first number (2n) is 20 more then the second (2n + 2).
2(2n) = 2n + 2 + 20
4n = 2n + 22
4n - 2n = 22
2n = 22
n = 11
Now use n = 11 to find the 3 consecutive even numbers.
1st even number = 2(11) = 22
2nd even number = 2(11) + 2 = 24
3rd even number = 2(11) + 4 = 26
22, 24, 26
