Question

In your random sample of 25 Chips Ahoy bags, you find a mean of 985 chips per bag, with a standard deviation of 10 chips. Run a two-tailed significance test to see if you have evidence supporting Nabisco’s claim that Chips Ahoy bags contain about 1000 chips. The p-value for the test statistic is...

Answer 1

Answer:

The p -value is less than 0.001.

Step-by-step explanation:

Given information:

Sample size = 25 chips

Sample mean = 985

Sample standard deviation = 10

Let as assume that sample is distributed normally.

The formula for test statistic

$t=\frac{\overline{x}-\mu}{\frac{s}{\sqrt{n}}}$

where,

$\overline{x}$ is sample mean

μ is population mean.

s is sample standard deviation.

n is sample size.

The value of test statistic is

$t=\frac{985-1000}{\frac{10}{\sqrt{25}}}$

$t=\frac{985-1000}{\frac{10}{\sqrt{25}}}$

$t=-7.5$

The p-value is

$p=2\times p(t$

Therefore the p -value is less than 0.001.