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Andrej [43]
3 years ago
6

-11 -9 -7 -5 for n= 17

Mathematics
1 answer:
4vir4ik [10]3 years ago
4 0
Where is a n? please look at the question again!!
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What is the constant of proportionality between y and x in the graph? (WILL MARK BRAINLIST IF RIGHT!)
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What is the solution?<br> 6(1/3x+1/3)=3(x+4)
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Thompson and Thompson is a steel bolts manufacturing company. Their current steel bolts have a mean diameter of 149 millimeters,
Artemon [7]

Answer:

The probability that the sample mean would differ from the population mean by more than 0.5 millimeters is 0.2420.

Step-by-step explanation:

Let <em>X</em> = the diameter of the steel bolts manufactured by the steel bolts manufacturing company Thompson and Thompson.

The mean diameter of the bolts is:

<em>μ</em> = 149 mm.

The standard deviation of the diameter of bolts is:

<em>σ</em> = 5 mm.

A random sample, of size <em>n</em> = 49, of steel bolts are selected.

The population of the diameter of bolts is not known.

According to the Central Limit Theorem if we have a population with mean <em>μ</em> and standard deviation <em>σ</em> and we take appropriately huge random samples (<em>n</em> ≥ 30) from the population with replacement, then the distribution of the sample mean will be approximately normally distributed.

The mean of the sampling distribution of sample mean is:

\mu_{\bar x}=\mu=149\ mm

The standard deviation of the sampling distribution of sample mean is:

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{5}{\sqrt{49}}=0.7143

Compute the probability that the sample mean would differ from the population mean by more than 0.5 millimeters as follows:

P(\bar X>\bar x)=P(\frac{\bar X-\mu_{\bar x}}{\sigma _{\bar x}}>\frac{0.50}{0.7143})\\=P(Z>0.70)\\=1-P(Z

*Use a <em>z</em>-table for the probability.

Thus, the probability that the sample mean would differ from the population mean by more than 0.5 millimeters is 0.2420.

8 0
4 years ago
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