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BartSMP [9]
2 years ago
7

Which of the numbers below has a value that is between 3 and 4?

Mathematics
1 answer:
Vesnalui [34]2 years ago
4 0

Answer:

What are the options?

Step-by-step explanation:

I need to see the options!

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When studying radioactive​ material, a nuclear engineer found that over 365​ days, 1,000,000 radioactive atoms decayed to 973 co
HACTEHA [7]

Answer:

A. number of decayed atoms = 73.197

Step-by-step explanation:

In order to find the answer we need to use the radioactive decay equation:

N(t)=N0*e^{kt} where:

N0=initial radioactive atoms

t=time

k=radioactive decay constant

In our case, when t=0 we have 1,000,000 atoms, so:

1,000,000=N0*e^{k*0}

1,000,000=N0

Now we need to find 'k'. Using the provied information that after 365 days we have 973,635 radioactive atoms, we have:

973,635=1,000,000*e^{k*365}

ln(973,635/1,000,000)/365=k

-0.0000732=k

A. atoms decayed in a day:

N(t)=1,000,000*e^{-0.0000732t}

N(1)=1,000,000*e^{-0.0000732*1}

N(1)= 999,926.803

Number of atoms decayed in a day = 1,000,000 - 999,926.803 = 73.197

B. Because 'k' represents the probability of decay, then the probability that on a given day 51 radioactive atoms decayed is k=0.0000732.

4 0
3 years ago
Find the 14th term of the arithmetic sequence - 4x - 1, - 9x - 6 , -14x-11
Yanka [14]

Answer:

-69x-66

Step-by-step explanation:

1) given: a₁=-4x-1; a₂=-9x-6; a₃=-14x-11. Find: a₁₄-?

2) a₁₄=a₁+13d, where d - the difference between neighbor-terms;

3) d=a₂-a₁; ⇔ d= -9x-6+4x+1= -5x-5;

4) a₁₄= -4x-1+13*(-5x-5)= -69x-66.

3 0
2 years ago
6. Estimate by clustering: 56.9, 63.2, 59.3, 61.1<br><br> A. 240.0<br><br> B. 200.0
Andre45 [30]
B!!!!!!!!!! The answer is 200

EXPLANATION

Added sum is estimated to 200
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3 years ago
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Please help asap i really need it.
pishuonlain [190]
Slope is 2/1 , because the formula to find the slope is rise/ run
= 6/3
= 2/1
3 0
3 years ago
An equation is shown below:
tatyana61 [14]
The beginning steps to solve the equation 6(3x - 7) = 2 is
Step 1: 18x - 42 = 2
Step 2: 18x = 44
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3 years ago
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