Answer: the answer is Triangles BCP and CDP are condruent
Step-by-step explanation:
<span>x² + y² + 14x − 4y − 28 = 0
x² +14x +y² - 4y =28
x²+2*7x +7² -7² + y² - 2*2y +2² - 2² = 28
(x+7)² + (y-2)² -7²-2² =28
</span>(x+7)² + (y-2)²=28+49+4
(x+7)² + (y-2)² =81 is the answer.
Answer:
d
Step-by-step explanation:
Solution by substitution method
y=7x+8
∴y-7x=8
and y=x+20
∴y-x=20
Suppose,
-7x+y=8→(1)
and -x+y=20→(2)
Taking equation (1), we have
-7x+y=8
⇒y=7x+8→(3)
Putting y=7x+8 in equation (2), we get
-x + 7x + 8 = 20
6x = 20-8
6x = 12
x= 12 / 6
x = 2
substitute for x in equation (3)
y = 7(x) + 8
y = 7(2) + 8
y = 22
Answer:
The remaining solution to the equation is x = 1
Step-by-step explanation:
2x^2 + x - 1 = 2
First set the equation to zero by subtracting 2 from each side:
2x^2 + x - 1 - 2 = 2 - 2
2x^2 + x - 3 = 0
Factor the left side of the equation:
2x^2 + x - 3 = 0
(2x + 3)(x - 1) = 0
Now set each factor to zero and solve:
2x+ 3 = 0
2x+ 3 - 3 = 0 - 3
2x= -3
2x/2= -3/2
x= -3/2 (The given expression)
x - 1 = 0
x - 1 + 1 = 0 + 1
x = 1
Since we already knew x = -3/2, the missing solution is x = 1.
Answer: I think that the answer is 1773.14
Step-by-step explanation:
