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slavikrds [6]
3 years ago
14

A train must climb a constant gradient of 5.5m for every 200m on track. Find the angle of incline

Mathematics
2 answers:
Eduardwww [97]3 years ago
4 0
<span>angle = arcsin(5.5/200) = 1.575 degrees</span>
elena55 [62]3 years ago
3 0
1.575 degrees is the answer
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Charlie is evaluating the product of 0.09 and 0.05. He multiplies, and before placing the decimal, arrives at an answer of 45. A
almond37 [142]
The answer is .0045 because you move the decimal place 4 times to the left.
6 0
3 years ago
Read 2 more answers
A 55m and 35m broad park is surrounded by a 2.5m wide path.
daser333 [38]

Step-by-step explanation:

☄ \underline {\underline{ \text{Given}}} :

  • Length of a park ( l ) = 55 m
  • Breadth of a park ( b ) = 35 m
  • Width running outside the park ( d ) = 2.5 m
  • Rate of paving the path with stones = Rs 120 per sq.metre

☄ \underline{ \underline{ \text{To \: find}}}:

  • Area of the park
  • Cosy of paving the path with stones at Rs 130 per sq.metre

☄ \underline{ \underline{ \text{Solution}}} :

Part 1 : \boxed{\text{Area \:of \:a \:path \: running \:outside = 2d(l + b + 2d)}}

plug the known values and simplify :

⟹ \sf{2 \times 2.5(55 + 35 + 2 \times 2.5)}

⟹ \sf{5  \times 95}

⟹ \sf{475 \:  {m}^{2} }

Part 2 : \boxed{ \sf{Total \: cost = Area \: of \: paths \:  \times  Rate}}

⟹ \sf{475  \times 120}

⟹\sf{Rs \: 57000}

\purple{ \boxed{ \boxed{ \sf{ \tt{⟿ \: Our \: final \: answer : (i) = 475 \:  {m}^{2}   \:  and \: (ii ) = Rs \: 57000}}}}}

Hope I helped ! ♡

Have a wonderful day /night ツ

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7 0
3 years ago
The population of Adamsville grew from 7,000 to 12,000 in 5 years. Assuming uninhibited exponential growth, what is the expected
mr Goodwill [35]
We have that if we assume standard exponential growth, the equation of the population will be:7000*e^{kt} if we start counting from the moment that the population was 7000. We are given that 7000* e^{5k}=12000, namely that P(5)=12000 and we need to find 7000e^{(5+5)k}=7000e^{10k}. Since e^(10k)=e^(5k)*e^(5k), and since we can solve for e^(5k) from P(5), we have:
e^(5k)=12000/7000 and we can calculate P(10). P(10)=7000\frac{12000^2}{7000^2}= 20571 people.
3 0
3 years ago
Frank started an assignment at 6:26 PM and finished it at 7:44 PM. How long did it take him? Give your answer in minutes.
Svet_ta [14]
7.44-6.26=1.18
1.18 in minutes is 78 minutes bc 1 hour is 60 minutes + 18 minutes is 78
Hope this helps :D
5 0
2 years ago
Read 2 more answers
Need help plz its on the screenshot
user100 [1]
The answers are a and c
4 0
3 years ago
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