Answer:
Volume = 16 unit^3
Step-by-step explanation:
Given:
- Solid lies between planes x = 0 and x = 4.
- The diagonals rum from curves y = sqrt(x) to y = -sqrt(x)
Find:
Determine the Volume bounded.
Solution:
- First we will find the projected area of the solid on the x = 0 plane.
A(x) = 0.5*(diagonal)^2
- Since the diagonal run from y = sqrt(x) to y = -sqrt(x). We have,
A(x) = 0.5*(sqrt(x) + sqrt(x) )^2
A(x) = 0.5*(4x) = 2x
- Using the Area we will integrate int the direction of x from 0 to 4 too get the volume of the solid:
V = integral(A(x)).dx
V = integral(2*x).dx
V = x^2
- Evaluate limits 0 < x < 4:
V= 16 - 0 = 16 unit^3
Answer:
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Step-by-step explanation:
Answer:
11. 
12. 
13. 
14. 
15. 
16. 
17. 
18. 
Step-by-step explanation:
In all of them you just subtract the bottom exponent from the top exponent.
Answer:
232 = CCXXXII
233 = CCXXXIII
234 = CCXXXIV
235 = CCXXXV
236 = CCXXXVI
Step-by-step explanation:
