Given:
In the given circle O, BC is diameter, OA is radius, DC is a chord parallel to chord BA and
.
To find:
The
.
Solution:
If a transversal line intersect two parallel lines, then the alternate interior angles are congruent.
We have, DC is parallel to BA and BC is the transversal line.
[Alternate interior angles]


In triangle AOB, OA and OB are radii of the circle O. It means OA=OB and triangle AOB is an isosceles triangle.
We know that base angles of an isosceles triangle are congruent.
[Base angles of an isosceles triangle]


In triangle AOB,





Therefore, the measure of angle AOB is 120 degrees.
It would actually be -14 because 5+4-2=7 and if you multiply 7 by -2 you get -14
Add up the subtended arcs that these chords cut to get
44+86 = 130
Then divide that result by 2
130/2 = 65
Final Answer: choice A) 65 degrees
Answer:
No mode.
Step-by-step explanation:
No mode.
None of the numbers repeat and since the mode is the most frequent number there isn't one.