Answer:
0.0045248 ;
0.1312218 ;
0.0001809 ;
0.1659729
Step-by-step explanation:
Number of Kings in deck = 4
Total number of cards in deck = 52
Picking without replacement :
A = King on first draw :
P(A) = 4 / 52
A = King on 2nd draw :
P(B) = 3 / 51
A = King on 3rd draw :
P(C) = 2 / 50
1.) P(A n B) = P(A) * P(B)
P(A n B) = 4/52 * 3/51 = 12 / 2652 = 0.0045248
2.) P(A u B) = P(A) + P(B) - P(AnB)
P(AuB) = 4/52 + 3/51 - 0.0045248 = 0.1312218
3.) P(A ∩ B ∩ C) = P(A) * P(B) * P(C)
P(A ∩ B ∩ C) = 4/52 * 3/51 * 2/50 = 0.0001809
4.) P(A U B U C) =
P(A) + P(B) + P(C) - P(AnB) - P(AnC) - P(BnC) - P(AnBnC)
P(AnC) = P(A) * P(C) = 4/52 * 2/50 = 0.0030769
P(BnC) = P(B) * P(C) = 3/51 * 2/50 = 0.0023529
4/52 + 3/51 + 2/50 - 0.0045248 - 0.0030769 - 0.0023529 + 0.0001809 = 0.1659729
The numbers are x and y
x>y
x=5+2y
x-y=13
so
sub 5+2y for x
5+2y-y=13
5+y=13
y=8
sub back
x-y=13
x-8=13
21=x
the numbres are 21 and 8
Answer:
(x2 + 7) = 3
x2 = 3 - 7
x2 = - 4
x doesn't have a solution
1) suppose for purposes of calculation that the cake <span>is </span><span>inscribed in a square</span> of 8 by 8
the area of 1 cake=8*8=64 in²
the rectangular table area=576 in²-----> I assume square table 24 in x 24 in
576/64= 9----------- > Sue has baked 9 cakes
if just 1 <span>carrot cake
</span>then
(9-1)=8 ----------> <span>coffee cakes and lemon cakes
we know that </span><span>equal numbers of coffee cakes and lemon cakes
</span>therefore
coffee cakes=8/2=4
lemon cakes=4
carrot cake=1
the answer part 1) is
<span>the dimensions of the table are 24 in x 24 in
</span>the answer part 2) is
Sue has baked 9 cakes
coffee cakes=4
lemon cakes=4
carrot cake=1
part 3) distribution of the cakes in the table 24 in x 24 in
answer
let
Z------->carrot cake
C------->coffee cakes
L------->lemon cakes
Z-C-L or C-L-C
C-L-C Z-C-L
L-C-L C-L-C
