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madreJ [45]
3 years ago
13

Select the expression that is equivalent to (x2 + 7) = 3

Mathematics
1 answer:
Sedbober [7]3 years ago
4 0

Answer:

(x2 + 7) = 3

x2 = 3 - 7

x2 = - 4

x doesn't have a solution

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The mens taxable is income is rs 14280 the state tex instruction tel him to pay 2%on the first rs3000 of his taxable incom 3% on
Naddik [55]

Answer:

Rs. 451.2

Step-by-step explanation:

It is given that a men's total taxable income is Rs. 14,280.

He is charged by the state tax for 2% on the first Rs. 3000.

i.e. $2 \% \times 3000$

   $=\frac{2}{100} \times 3000$

  = Rs. 60

Then he is asked to pay 3% on the second Rs. 3000

i.e. $3 \% \times 3000$

   $=\frac{3}{100} \times 3000$

  = Rs. 90

Similarly, he pays 3% on the third Rs. 3000

i.e. $3 \% \times 3000$

   $=\frac{3}{100} \times 3000$

  = Rs. 90

Lastly, he pays 4% on the remaining amount. i.e 14,280 - (3000+3000+3000) = 14,280 - 9000 = Rs. 5280

∴$4 \% \times 5280 $

   $=\frac{4}{100} \times 5280$

  = Rs. 211.2

Thus the total amount of the income tax the man has to pay is

= 60+90+90+211.2

= Rs. 451.2

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3 years ago
Ten years ago, only 20% of the u.s. population consisted of people more than 65 years old. a researcher plans to use a sample of
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NO LINKS!!! Find the arc measure and arc length of AB. Then find the area of the sector ABQ.​
Norma-Jean [14]

Answer:

<u>Arc Measure</u>:  equal to the measure of its corresponding central angle.

<u>Formulas</u>

\textsf{Arc length}=2 \pi r\left(\dfrac{\theta}{360^{\circ}}\right)

\textsf{Area of a sector of a circle}=\left(\dfrac{\theta}{360^{\circ}}\right) \pi r^2

\textsf{(where r is the radius and the angle }\theta \textsf{ is measured in degrees)}

<h3><u>Question 39</u></h3>

Given:

  • r = 7 in
  • \theta = 90°

Substitute the given values into the formulas:

Arc AB = 90°

\textsf{Arc length of AB}=2 \pi (7) \left(\dfrac{90^{\circ}}{360^{\circ}}\right)=3.5 \pi=11.00\:\sf in\:(2\:d.p.)

\textsf{Area of the sector AQB}=\left(\dfrac{90^{\circ}}{360^{\circ}}\right) \pi (7)^2=\dfrac{49}{4} \pi=38.48\:\sf in^2\:(2\:d.p.)

<h3><u>Question 40</u></h3>

Given:

  • r = 6 ft
  • \theta = 120°

Substitute the given values into the formulas:

Arc AB = 120°

\textsf{Arc length of AB}=2 \pi (6) \left(\dfrac{120^{\circ}}{360^{\circ}}\right)=4\pi=12.57\:\sf ft\:(2\:d.p.)

\textsf{Area of the sector AQB}=\left(\dfrac{120^{\circ}}{360^{\circ}}\right) \pi (6)^2=12 \pi=37.70\:\sf ft^2\:(2\:d.p.)

<h3><u>Question 41</u></h3>

Given:

  • r = 12 cm
  • \theta = 45°

Substitute the given values into the formulas:

Arc AB = 45°

\textsf{Arc length of AB}=2 \pi (12) \left(\dfrac{45^{\circ}}{360^{\circ}}\right)=3 \pi=9.42\:\sf cm\:(2\:d.p.)

\textsf{Area of the sector AQB}=\left(\dfrac{45^{\circ}}{360^{\circ}}\right) \pi (12)^2=18 \pi=56.55\:\sf cm^2\:(2\:d.p.)

8 0
2 years ago
Can anyone explain how you got the answer please.
Ipatiy [6.2K]

Answer:

Option A

Step-by-step explanation:

The first thing we want to do here is identify whether or not the diagonals are perpendicular, which helps much to know to prove what angle AOB.

_____

Let us say that this is a rhombus. That would make the diagonals perpendicular, and hence ∠AOB should be 90 degrees, but let's not jump to conclusions. We need to calculate the length of BO. By Pythagorean Theorem it should be the following length -

( BC )^2 = ( BO )^2 + ( OC )^2,\\( 10 )^2 = ( BO )^2 + ( 7.8 )^2,\\100 = BO^2 + 60.84,\\BO^2 = 39.16,\\\\BO = ( About ) 6.26\\

_____

Knowing BO, to prove that this is a rhombus we can find the length of BO another way, and match it to the length 6.26 -

Δ ABD = Equilateral,

BD = 10 cm,

" Coincidence Theorem " - BO = 5 = OD.

Here BO = 5. 5 is close to 6.26 but not exactly, so the measure of angle AOB is not 90, but better yet 80.

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Rebecca is playing a video game that involves planting and cutting down trees. She moves up an energy level for each tree she pl
yarga [219]

Answer:

After turn one she will have 0 points

After turn 2 she will have 8 points

After turn 3 she will have 7 points

She will not earn bonus points because she could not reach ten points

Hope this helps :)

8 0
4 years ago
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