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saw5 [17]
3 years ago
6

Show me how to solve 48 divided by 3

Mathematics
1 answer:
Papessa [141]3 years ago
3 0

Answer:

16 3 goes into 48 16 times.

Step-by-step explanation:

48÷3 = 16 3+3+3+3+3+3+3+3+3+3+3+3+3+3+3+3=48

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3 2/3 - 2 3/4= ______________
NISA [10]

Answer:

7  5/12

Step-by-step explanation:

3+2=6

2/3 + 3/4 = 8/12 + 9/12 = 17/12 = 1   5/12

1 + 6= 7 5/12

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3 years ago
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What is the cosine ration ? HELP PLZ !!
garik1379 [7]

The cosine of angle X is

\cos X=\dfrac{XY}{XZ}=\dfrac{XY}{7.5}

By the Pythagorean theorem, we have

XY^2+YZ^2=XZ^2\implies XY=\sqrt{7.5^2-6^2}=4.5

Then

\cos X=\dfrac{XY}{XZ}=\dfrac{4.5}{7.5}

Multiplying numerator and denominator by 2, we get \dfrac9{15}.

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3 years ago
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Find the value of y so that the line passing through the two points have the given slope (2,3) (7,y) m=-2/5
Liono4ka [1.6K]

Answer:

y = 1

Step-by-step explanation:

Find the slope of the line passing through the points (2,3) and (7,y):

m=\dfrac{y-3}{7-2}=\dfrac{y-3}{5}

The slope of the line is equal to

m=-\dfrac{2}{5},

then

\dfrac{y-3}{5}=-\dfrac{2}{5}\\ \\y-3=-2\\ \\y=-2+3\\ \\y=1

8 0
3 years ago
A line passes through the points (-7, 2) and (1, 6).A second line passes through the points (-3, -5) and (2, 5).Will these two l
BlackZzzverrR [31]

Answer:

Yes, the lines intersect at (3,7). The solution is (3,7).

Explanation:

Step 1. The first line passes through the points:

(-7,2) and (1,6)

and the second line passes through the points:

(-3,-5) and (2,5)

Required: State if the lines intersect, and if so, find the solution.

Step 2. We need to find the slope of the lines.

Let m1 be the slope of the first line and m2 be the slope of the second line.

The formula to find a slope when given two points (x1,y1) and (x2,y2) is:

m=\frac{y_2-y_1}{x_2-x_1}

Using our two points for each line, their slopes are:

\begin{gathered} m_1=\frac{6-2}{1-(-7)} \\  \\ m_2=\frac{5-(-5)}{2-(-3)} \end{gathered}

The results are:

\begin{gathered} m_1=\frac{6-2}{1-(-7)}=\frac{4}{1+7}=\frac{4}{8}=\frac{1}{2} \\  \\  \end{gathered}m_2=\frac{5+5}{2+3}=\frac{10}{5}=2

The slopes are not equal, this means that the lines are NOT parallel, and they will intersect at some point.

Step 3. To find the intersection point (the solution), we need to find the equation for the two lines.

Using the slope-point equation:

y=m(x-x_1)+y_1

Where m is the slope, and (x1,y1) is a point on the line.

For the first line m=1/2, and (x1,y1) is (-7,2). The equation is:

y=\frac{1}{2}(x-(-7))+2

Solving the operations:

\begin{gathered} y=\frac{1}{2}(x+7)+2 \\ \downarrow\downarrow \\ y=\frac{1}{2}x+7/2+2 \\ \downarrow\downarrow \\ y=\frac{1}{2}x+5.5 \end{gathered}

Step 4. We do the same for the second line. The slope is 2. and the point (x1,y1) is (-3, -5). The equation is:

\begin{gathered} y=2(x-(-3))-5 \\ \downarrow\downarrow \\ y=2x+6-5 \\ \downarrow\downarrow \\ y=2x+1 \end{gathered}

Step 5. The two equations are:

\begin{gathered} y=\frac{1}{2}x+5.5 \\ y=2x+1 \end{gathered}

Now we need to solve for x and y.

Step 6. Equal the two equations to each other:

\frac{1}{2}x+5.5=2x+1

And solve for x:

\begin{gathered} \frac{1}{2}x+5.5=2x+1 \\ \downarrow\downarrow \\ 5.5-1=2x-\frac{1}{2}x \\ \downarrow\downarrow \\ 4.5=1.5x \\ \downarrow\downarrow \\ \frac{4.5}{1.5}=x \\ \downarrow\downarrow \\ \boxed{3=x} \end{gathered}

Step 7. Use the second equation:

y=2x+1

and substitute the value of x to find the value of y:

\begin{gathered} y=2(3)+1 \\ \downarrow\downarrow \\ y=6+1 \\ \downarrow\downarrow \\ \boxed{y=7} \end{gathered}

The solution is x=3 and y=7, in the form (x,y) the solution is (3,7).

Answer:

Yes, the lines intersect at (3,7). The solution is (3,7).

6 0
1 year ago
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