Answer:
can't understand the question.
Answer:
7.5 Quarts
Step-by-step explanation:
D'Naisa mixed the following:
- 1 gallon of orange paint
- 2 quarts of yellow paint
- 3 pints of red paint.
We are to determine in total, the number of quarts of paint that she mixed. this is done by converting each of the volume to quart.
<u>1 gallon of orange paint</u>
- 1 gallon = 4 Quarts
- Orange Paint=4 Quarts
<u>3 pints of red paint.</u>
- 1 pint =0.5 quart
- 3 Pints =3 X 0.5 Quart
- =1.5 Quart of red paint
Therefore,
Total Volume of Paint Mixed in quart= Volume of Orange+Yellow+Red
=4+2+1.5
=7.5 Quarts
Answer:
17.5% per annum
Step-by-step explanation:
<u>Given:</u>
Money invested = $20,000 at the age of 20 years.
Money expected to be $500,000 at the age of 40.
Time = 40 - 20 = 20 years
<em>Interest is compounded annually.</em>
<u>To find:</u>
Rate of growth = ?
<u>Solution:</u>
First of all, let us have a look at the formula for compound interest.
Where A is the amount after T years compounding at a rate of R% per annum. P is the principal amount.
Here, We are given:
P = $20,000
A = $500,000
T = 20 years
R = ?
Putting all the values in the formula:
![500000 = 20000 \times (1+\frac{R}{100})^{20}\\\Rightarrow \dfrac{500000}{20000} =(1+\frac{R}{100})^{20}\\\Rightarrow 25 =(1+\frac{R}{100})^{20}\\\Rightarrow \sqrt[20]{25} =1+\frac{R}{100}\\\Rightarrow 1.175 = 1+0.01R\\\Rightarrow R \approx17.5\%](https://tex.z-dn.net/?f=500000%20%3D%2020000%20%5Ctimes%20%281%2B%5Cfrac%7BR%7D%7B100%7D%29%5E%7B20%7D%5C%5C%5CRightarrow%20%5Cdfrac%7B500000%7D%7B20000%7D%20%3D%281%2B%5Cfrac%7BR%7D%7B100%7D%29%5E%7B20%7D%5C%5C%5CRightarrow%2025%20%3D%281%2B%5Cfrac%7BR%7D%7B100%7D%29%5E%7B20%7D%5C%5C%5CRightarrow%20%5Csqrt%5B20%5D%7B25%7D%20%3D1%2B%5Cfrac%7BR%7D%7B100%7D%5C%5C%5CRightarrow%201.175%20%3D%201%2B0.01R%5C%5C%5CRightarrow%20R%20%5Capprox17.5%5C%25)
So, the correct answer is <em>17.5% </em>per annum and compounding annually.
Where is the diagram? How do we answer without it?
Answer:
3.4625
Step-by-step explanation:
Given the equation:
Q(t)=0.05t^2 + 0.1t + 3.4 parts per million
Where t = time in years
By approximately how much will the carbon monoxide lvel change during the coming 6 months?
t = 6 months = 6/12 = 0.5 year
Q(0.5) = 0.05(0.5)^2 + 0.1(0.5) + 3.4 parts per million
Q(0.5) = 0.05(0.25) + 0.05 + 3.4
Q(0.5) = 0.0125 + 0.05 + 3.4
Q = 3.4625
Carbon monoxide level will change by approximately 3.4625 parts per million in 6 months
