Ask question

Ask question

All categories

3 years ago

8

92 divied by 20,884 long division

1 answer:

guajiro [1.7K]3 years ago

7 0

Answer:

brainliest is appreciated

You might be interested in

PLEASE HELP VERY URGENT!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

diamong [38]

Q1. Look at the picture.

$C.\\y=-\dfrac{1}{3}x+3\\\\y=2x-4$

Q2. Look at the picture.

$A.\ 4-t$

Q3.

Put the value of x = 2 to the equation 3x + y = 5:

$3(2)+y=5$

$6+y=5$ <em>subtract 6 from both sides</em>

$y=-1\\\\F.\ -1$

Q4.

$\left\{\begin{array}{ccc}n=3m-11&(*)\\2m+3n=0&(**)\end{array}\right$

Substitute (*) to (**):

$2m+3(3m-11)=0$ <em>use distributive property</em>

$2m+(3)(3m)+(3)(-11)=0$

$2m+9m-33=0$ <em>add 33 to both sides</em>

$11m=33$ <em>divide both sides by 11</em>

$m=3$

Put the value of m to (*):

$n=3(3)-11\\\\n=9-11\\\\n=-2$

$C. (3,\ -2)$

Q5.

w - width

3w - length

24 in - the sum of length and width

The equation:

$w+3w=24$

$4w=24$ <em>divide both sides by 4</em>

$w=6\ in$

$3w=3(6)=18\ in$

$J.\ 18\ inches$

7 0

3 years ago

Read 2 more answers

A bicycle has a listed price of $813.95 before tax. If the sales tax rate is 8.5%, find the total cost of the bicycle with sales

Nesterboy [21]

Answer:

$883.14

Step-by-step explanation:

Have a great day! ;)

4 0

3 years ago

Read 2 more answers

A fence must be built to enclose a rectangular area of 45 comma 000 ftsquared. Fencing material costs $ 3 per foot for the two s

Tatiana [17]

Answer:

150 feet by 300 feet.

Step-by-step explanation:

The fence is to enclose a rectangular area of 45,000 ft squared.

If the dimensions of the rectangle are x and y

Area of a rectangle = xy

xy=45000
$x=\frac{45000}{y}$

Perimeter of the Rectangle =2x+2y

Fencing material costs $ 3 per foot for the two sides facing north and south and $6 per foot for the other two sides.

Cost of Fencing, C=$(6*2x+3*2y)=$(12x+6y)

Substitute $x=\frac{45000}{y}$ into the Cost to get C(y)

C=12x+6y

$C(y)=12(\frac{45000}{y})+6y\\C(y)=\frac{540000+6y^2}{y}$

The value at which the cost is least expensive is at the minimum point of C(y), when the derivative is zero.

$C^{'}(y)=\dfrac{6y^2-540000}{y^2}$

$\dfrac{6y^2-540000}{y^2}=0\\6y^2-540000=0\\6y^2=540000\\y^2=\frac{540000}{6} =90000\\y=\sqrt{90000}=300$

Recall,

$x=\frac{45000}{y}=\frac{45000}{300}=150$

Since x=150, y=300

The dimensions that will be least expensive to build is 150 feet by 300 feet.

6 0

3 years ago

Jasmine knows that the area of a rectangle is the product of its base and height. Help her write an expression that represents t

Andrews [41]

Answer:

8b and 80

Step-by-step explanation:

6 0

3 years ago

2 1⁄2 ÷ 1 3⁄6 please help me with the RIGHT answer.

ycow [4]

Answer:

$1\frac{2}{3}$

Step-by-step explanation:

We want to simplify:

$2 \frac{1}{2} \div 1 \frac{3}{6}$

This is the same as:

$2 \frac{1}{2} \div 1 \frac{1}{2}$

Now let us convert the mixed numbers to improper fractions.

$\frac{5}{2} \div \frac{3}{2}$

We multiply by the reciprocal of the second fraction to get:

$\frac{5}{2} \times \frac{2}{3}$

Cancel out the common factors to obtain:

$\frac{5}{3} = 1 \frac{2}{3}$

5 0

3 years ago