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topjm [15]
4 years ago
8

At a raffle, 1000 tickets are sold for $5 each. There are 20 prizes of $25, 5 prizes of $100, and 1 grand prize of $2000. Suppos

e you buy one ticket.
Mathematics
1 answer:
KengaRu [80]4 years ago
6 0
What needs to be solved?
You might be interested in
All help is much appreciated I really need it please
svetoff [14.1K]
The two traingles, VSU and TSR are similar by SAS similarity criteria.

According to the diagram,
UT = TS
and
VR = SR


\frac{ST}{SU}  =  \frac{ST}{ST + SU}   \\ =  \frac{ST}{2ST}   =  \frac{1}{2}

Similarly for all sides the ratio must be same.
Applying this on the side required here,

\frac{RT}{VU}  =  \frac{1}{2}   \\  \\  \frac{p - 6}{p}   =  \frac{1}{2}  \\  2p - 12 = p \\  p = 12


Therefore p = 12 units= UV .
6 0
3 years ago
Slope= -3; (1, 2) is on the line
wolverine [178]

Step-by-step explanation:

By 2 point form

y-y1= m(x-x1)

y-2 = -3(x-1)

y-2=-3x+3

3x+y=5... this is the required line

7 0
3 years ago
Find the value of x and y in each triangle
kykrilka [37]
Y = 8/cos60 = 16
x = sqr(16^2 + 8^2) = 8sqr(3) = 13.86 approx

3 0
3 years ago
Read 2 more answers
have The Shroud of Turin, which shows the negative image of the body of a man who appears to have been crucified, is believed by
Jlenok [28]

Answer:94%

Step-by-step explanation:

Half life of a radioactive element is the time taken for half it's mass to disintegrate away.it means after attaining half life,what will be left is 100-50=50%.

Let the 100% mass of C-14,be x

Then 5730years=1/2 of X

Then 660 years=y of X

Where Y is the fraction of C-14 that has disintegrate as at 1988.

5730/660=1/2X/yX

5730/660=1/2/y

Cross multiplying

5730×y=660×1/2

5730y=330

Y=330/5730=0.05759

In %,5.76%

Amount of C-14 left is

100-5.76=94.24=94% as at 1988.

5 0
4 years ago
What is the answer of factor of 120
ahrayia [7]
(10)(12)




I hope I helped
6 0
4 years ago
Read 2 more answers
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