The two traingles, VSU and TSR are similar by SAS similarity criteria.
According to the diagram,
UT = TS
and
VR = SR
Similarly for all sides the ratio must be same.
Applying this on the side required here,
Therefore p = 12 units= UV .
Step-by-step explanation:
By 2 point form
y-y1= m(x-x1)
y-2 = -3(x-1)
y-2=-3x+3
3x+y=5... this is the required line
Y = 8/cos60 = 16
x = sqr(16^2 + 8^2) = 8sqr(3) = 13.86 approx
Answer:94%
Step-by-step explanation:
Half life of a radioactive element is the time taken for half it's mass to disintegrate away.it means after attaining half life,what will be left is 100-50=50%.
Let the 100% mass of C-14,be x
Then 5730years=1/2 of X
Then 660 years=y of X
Where Y is the fraction of C-14 that has disintegrate as at 1988.
5730/660=1/2X/yX
5730/660=1/2/y
Cross multiplying
5730×y=660×1/2
5730y=330
Y=330/5730=0.05759
In %,5.76%
Amount of C-14 left is
100-5.76=94.24=94% as at 1988.
