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AleksAgata [21]
4 years ago
14

QUESTION 27Find the value of p in the equation 2p over 7=7​

Mathematics
1 answer:
ASHA 777 [7]4 years ago
5 0

Answer:

24.5

Step-by-step explanation:

2p/7 = 7

cross multiply

2p = 49

p = 24.9

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The perimeter of a rectangular section of a roof is 96 yards. The length is 18 yards. What equation could you use to find the wi
Kruka [31]

Answer:

36+2w=96

2w=96-36=60

w=60/2=30

Step-by-step explanation:

perimeter is 96, that means length + length + width + width = 96.

say l is length and w is width.

since we know length is 18, 18+18+width+width = 96

36+2w=96

2w=96-36=60

w=60/2=30

4 0
3 years ago
Read 2 more answers
Two machines are used for filling glass bottles with a soft-drink beverage. The filling process have known standard deviations s
stellarik [79]

Answer:

a. We reject the null hypothesis at the significance level of 0.05

b. The p-value is zero for practical applications

c. (-0.0225, -0.0375)

Step-by-step explanation:

Let the bottles from machine 1 be the first population and the bottles from machine 2 be the second population.  

Then we have n_{1} = 25, \bar{x}_{1} = 2.04, \sigma_{1} = 0.010 and n_{2} = 20, \bar{x}_{2} = 2.07, \sigma_{2} = 0.015. The pooled estimate is given by  

\sigma_{p}^{2} = \frac{(n_{1}-1)\sigma_{1}^{2}+(n_{2}-1)\sigma_{2}^{2}}{n_{1}+n_{2}-2} = \frac{(25-1)(0.010)^{2}+(20-1)(0.015)^{2}}{25+20-2} = 0.0001552

a. We want to test H_{0}: \mu_{1}-\mu_{2} = 0 vs H_{1}: \mu_{1}-\mu_{2} \neq 0 (two-tailed alternative).  

The test statistic is T = \frac{\bar{x}_{1} - \bar{x}_{2}-0}{S_{p}\sqrt{1/n_{1}+1/n_{2}}} and the observed value is t_{0} = \frac{2.04 - 2.07}{(0.01246)(0.3)} = -8.0257. T has a Student's t distribution with 20 + 25 - 2 = 43 df.

The rejection region is given by RR = {t | t < -2.0167 or t > 2.0167} where -2.0167 and 2.0167 are the 2.5th and 97.5th quantiles of the Student's t distribution with 43 df respectively. Because the observed value t_{0} falls inside RR, we reject the null hypothesis at the significance level of 0.05

b. The p-value for this test is given by 2P(T0 (4.359564e-10) because we have a two-tailed alternative. Here T has a t distribution with 43 df.

c. The 95% confidence interval for the true mean difference is given by (if the samples are independent)

(\bar{x}_{1}-\bar{x}_{2})\pm t_{0.05/2}s_{p}\sqrt{\frac{1}{25}+\frac{1}{20}}, i.e.,

-0.03\pm t_{0.025}0.012459\sqrt{\frac{1}{25}+\frac{1}{20}}

where t_{0.025} is the 2.5th quantile of the t distribution with (25+20-2) = 43 degrees of freedom. So

-0.03\pm(2.0167)(0.012459)(0.3), i.e.,

(-0.0225, -0.0375)

8 0
3 years ago
The solution set of n2 − 14n = -45 is {}.
Sphinxa [80]
N=5 or n=9 can be either one 
Hope this helped 
4 0
3 years ago
If you need two gallons, which store should you buy from? First store Second store They are the same price There is not enough i
Reika [66]
Not enough info. We dont have the prices from the stores
4 0
3 years ago
Please help me with this math question
Neko [114]

Answer:

C .56

Step-by-step explanation:

well thier are 5 days that are less then 3 days and theirs 9 days in total so you would do 5/9  to get the chance of it being less then 3 days.

5/6 = .555556

3 0
3 years ago
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