Answer:
a. mean = 1000
standard deviation = 4358.9
b. expected value of average damage bar Y = 1000
probability bar y exceeds 2000 = 0.011
Step-by-step explanation:
we have p1 = 95%, y1 = 0, p2 = 5%, y2 = 20000
Mean = (0.95 * 0) + (0.05 * 20000)
= 1000
var(y) = E(y²) - E(Y)²
= we solve for E(y)²
= 0²*0.95 + 20000²*0.05
= 0 + 20000000
then the variance of y = 20000000 - 1000²
=20000000-1000000
= $19000000
standard deviation is the square root of variance
= √19000000
= 4358.9
2.
a. Expected value of average is also the mean = 1000
b. we are to find probability that barY exceeds 2000

= 1000/435.889
= 2.29
1-p(z≤2.29)
= 1 - 0.989
= 0.011
so the probability that barY exceeds 2000 is 0.011
X = 3
2(4x - 3) - 8 = 4 + 2x
1. Distribute
8x - 6 - 8 = 4 + 2x
2. Collect like terms
8x - 14 = 4 + 2x
3. Collect like terms again (add 14 and subtract 2x)
6x = 18
4. Divide by 6
x = 3
Answer:
h (x)=-16x^(2)+3x+35 =
x-intercept(s): (3+√224932,0),(3−√2249 32,0)
y-intercept(s): (0,35)
Vpyramid=1/3 times area of base times height
volume=1/3 times 18 square inches times 4in
volume=6 square inches times 4in
volume=24 cubic inches
the volume is 24 cubic inches