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strojnjashka [21]
4 years ago
8

What is the sum of a 7-term geometric series if the first term is 6, the last term is 24,576, and the common ratio is 4?

Mathematics
1 answer:
mash [69]4 years ago
6 0

Answer:

The sum is 32766.

Step-by-step explanation:

The 7 terms of the series are as follows:

n_i = 6\cdot 4^i\,\,\,\mbox{for}\,\,\, i=0,1,...,6

namely: 6, 24, 96, 384, 1536, 6144, 24576

and their sum is 32766.

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Answer:

7/10-44/100                                                                                                                            70-44

 100

=26/100

=13/50

Step-by-step explanation:

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B

Step-by-step explanation:

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3 years ago
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hammer [34]
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3 years ago
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43 base five to base seven
solong [7]
First convert to decimal:

43_5=4\cdot5^1+3\cdot5^0=20+3=23

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7 0
3 years ago
Atmospheric pressure decreases by about 11.8% for every 1000 meters you climb. The pressure at sea level is 1013 millibars (a un
erica [24]
At sea level, the pressure is 1013, that's when the altitude is at 0, sea level, let's see

\bf \textit{Periodic Exponential Decay}\\\\
A=I(1 - r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &1013\\
I=\textit{initial amount}\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &0\\
p=period\to &1000
\end{cases}
\\\\\\
1013=I(1-0.118)^{\frac{0}{1000}}\implies 1013=I\cdot 1\implies 1013=I

so, the inital amount is 1013, when t = 0,

\bf \textit{Periodic Exponential Decay}\\\\
A=I(1- r)^{\frac{t}{p}}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\to &1013\\
r=rate\to 11.8\%\to \frac{11.8}{100}\to &0.118\\
t=\textit{meters climbed}\to &t\\
p=period\to &1000
\end{cases}
\\\\\\
A=1013(1-0.118)^{\frac{t}{1000}}\implies A=1013(0.882)^{\frac{t}{1000}}

now, to check the atmospheric pressure at 4000, simply set t = 4000, to get A.


7 0
3 years ago
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