Am doing math and need help, don't understand it

In the hyperbola graph,how do you find the domain and range?

xxTIMURxx [149]

Step-by-step explanation:

<h2>y = ± 5⁄2 x</h2><h2>y = ± 5⁄2 xThe equation is the left half of the hyperbola. The domain is ( – ∞, – 1⁄5 ]. The range is ( – ∞, ∞ ). The vertical line test indicates that this is not the graph of a function.</h2>

3 0

3 years ago

Convert y+7=4(x-3) standard form

True [87]

Answer:

-4x+y = -5

Step-by-step explanation:

Y+7=4(x-3)

Y+7=4x-12

+7. +7

Y=4x-5

-4x+y=-5

7 0

3 years ago

6. The vertices of ALMN are L(7,4), M(7,16), and

max2010maxim [7]

Answer:

(a) LM=12 units, LN=35 units, MN=37 units

(b)8 84 units

(c) 210 square units

Step-by-step explanation:

(a)

Since points L and M have same x coordinates, it means they are in the same plane. Also, since the Y coordinates of L and N are same, they also lie in the same plane

Length $LM=\sqrt {(7-7)^{2}+(16-4)^{2}}=12 units$

Length $LN=\sqrt {(42-7)^{2}+(4-4)^{2}}=35 units$

Length $MN=\sqrt {(42-7)^{2}+(4-16)^{2}}=37 units$

Alternatively, since this is a right angle triangle, length MN is found using Pythagoras theorem where

$MN=\sqrt {(LN)^{2}+(LM)^{2}}=\sqrt {(12)^{2}+(35)^{2}}=37 units$

Therefore, the lengths LM=12 units, LN=35 units and MN=37 units

(b)

Perimeter is the distance all round the figure

P=LM+LN+MN=12 units+35 units+37 units=84 units

(c)

Area of a triangle is given by 0.5bh where b is base and h is height, in this case, b is LN=35 units and h=LM which is 12 units

Therefore, A=0.5*12*35= 210 square units

4 0

2 years ago

The width of a rectangle is the length minus 7 units. The area of the

AleksandrR [38]

Answer:

8 units

Step-by-step explanation:

here's your solution

=> let the length of rectangle be X

=> then width = x - 7

=> area = 8units

=>> area = length*width

=> area = x (x-7) = 8

=> x^2 - 7 = 8

=> now, x^2 - 7x - 8 = 0

=> factories the above equation by middle term split

=> x^2 - 7x - 8

=> x^2 - 8x + x - 8

=> take the common

=> x(x - 8) + 1(x - 8)

=> (x + 1) (x - 8)

neglect (x + 1) because this will in negative for X

=> x - 8 = 0

=> x = 8

=>so, x = 8

=>length = 8 units

3 0

2 years ago

How can the x-intercept and y-intercept be used to graph a linear equation

JulijaS [17]

Because a line always goes past the y-intercept and x-intercept. It's not always both, it can sometimes just be the x-intercept or the y-intercept.

When a line intersects these points, for example if a line was to intersect the x-axis then y would be equal to 0, and the opposite for the y-axis. If a line was to intersect the y-axis x would be equal to 0.

Therefore by using that knowledge, and the equation of the line [ y=mx+c or y-y1=m(x-x1) ], we can find the equation of our line. Of course you would need the gradient of that line (the value "m").

5 0

3 years ago