3 years ago

Help meeee, i need helppp

Mathematics

2 answers:

vazorg [7]3 years ago

8 0

Answer: The first one is A. 16 + 10 +10 +10 +10

The second one is 40 units^2

Step-by-step explanation:

amid [387]3 years ago

5 0

Answer:

Step-by-step explanation:

When you get all the areas together, the answer is A. Sorry i was late to help

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Find the Value of k that will make the function f(x) continuous everywhere.

cricket20 [7]

well, if that function f(x) were to be continuos on all subfunctions, that means that whatever value 7x + k has when x = 2, meets or matches the value that kx² - 6 has when x = 2 as well, so then 7x + k = kx² - 6 when f(2)

$f(x)= \begin{cases} 7x+k,&x\leqslant 2\\ kx^2-6&x > 2 \end{cases}\qquad \qquad f(2)= \begin{cases} 7(2)+k,&x\leqslant 2\\ k(2)^2-6&x > 2 \end{cases} \\\\[-0.35em] ~\dotfill\\\\ 7(2)+k~~ = ~~k(2)^2-6\implies 14+k~~ = ~~4k-6 \\\\\\ 14~~ = ~~3k-6\implies 20~~ = ~~3k\implies \cfrac{20}{3}=k$