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bezimeni [28]
2 years ago
6

The spinner shown below will be used to play a game. If the pointer on the spinner is spun 120 times, how many times would you e

xpect the pointer to stop on a color other than red?
Mathematics
1 answer:
MAVERICK [17]2 years ago
6 0

Answer:

90?

Step-by-step explanation:

im assuming it is a 4 color spinner, so I think it would be about 90 times

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If f(x) -V7-3, complete the following statement (round your answer
nikklg [1K]

Answer:

- 1.67

Step-by-step explanation:

f(x) = \frac{3}{7+2} - \sqrt{7-3}

    =  \frac{3}{9} - \sqrt{4}

    = \frac{1}{3} - 2

    = - 1 \frac{2}{3}

    = -1.6666666

    = -1.67

5 0
2 years ago
A/20 + 14/15 = 9/15 <br><br> Can i get some help?
KiRa [710]
Method 1:

\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |multiply\ both\ sides\ by\ 60\\\\60\cdot\dfrac{a}{20}+60\cdot\dfrac{14}{15}=60\cdot\dfrac{9}{15}\\\\3a+4\cdot14=4\cdot9\\\\3a+56=36\ \ \ \ |subtract\ 56\ from\ both\ sides\\\\3a=-20\ \ \ \ |divide\ both\ sides\ by\ 3\\\\\boxed{a=-\frac{20}{3}\to a=-6\frac{2}{3}}

Method 2.

\dfrac{a}{20}+\dfrac{14}{15}=\dfrac{9}{15}\ \ \ \ |subtract\ \dfrac{14}{15}\ form\ both\ sides\\\\\dfrac{a}{20}=-\dfrac{5}{15}\\\\\dfrac{a}{20}=-\dfrac{1}{3}\ \ \ \ |multiply\ both\ sides\ by\ 20\\\\\boxed{a=-\dfrac{20}{3}\to a=-6\frac{2}{3}}
3 0
3 years ago
An image is 2 units to the left of the pre-image.
stepladder [879]

Answer:

Santana's thinking is not correct, because the correct translation is 2 units to the left, not right.

Step-by-step explanation:

I just got that question and I got it right.

5 0
3 years ago
Read 2 more answers
Set up an equation to show (×+2)×5=y
Masteriza [31]
<span>5x+10 = y

Subtract 10 from both sides.

5x = y - 10

Divide both sides by 5.

x = 1/5y - 2

Plugin 1/5y - 2 for the y.
5(1/5y - 2)
1 - 10 + 10 = y

1 = y
<span>
</span><span>Your Answer(s)
</span><span>y = 1
</span></span>x = 1/5y - 2
<span>
</span>
4 0
3 years ago
How does drawing a rectangle support the idea of composing a larger unit from smaller units
pav-90 [236]

Answer:

When you think rectangles, you think areas. Small areas aggregate to form bigger ones.

If you drew a rectangle, it's easy to divide it into smaller units by simply taking a line through its midsection from one length to the other and one width to the other. One can either form smaller squares or rectangles from a larger one.

When that is one, you'd have taken the larger area of a rectangle which is simply the product of the value of its length and it's the breadth, and divided it into smaller units.

Cheers!

4 0
2 years ago
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