You don't have the graph icon here, so we'll have to graph this parabola without it.
Your parabola is y = -x^2 + 3., which resembles y = a(x-h)^2 + k. We can tell immediately that this parabola opens down and that the vertex is (0,3).
Plot (0,3). Besides being the vertex, this point is also the max. of the function.
Now calculate four more points. Choose four arbitrary x-values, such as {-2, 1, 4, 5} and find the y value for each one. Plot the resulting four points. Draw a smooth curve thru them, remembering (again) that the vertex is at (0,3) and that the parabola opens down.
Answer: the answer is y=-22x+86
here is why:
the slope is -22 which is the m --> y=mx+b the point is (4,-2) the x=4 and y= =2
If we set up the equation:
-2= -22(4)+86
-2= -88+86
-2= -2
Answer:
x = 76.80°
4x - 142 = 165.18°
x/5 = 15.36°
5x/9 + 60 = 102.66°
Step-by-step explanation:
Total angle in a quadrilateral is 360
x + 4x - 142 + x/5 + (5/9)x + 60 = 360
259x/45 + - 82 = 360
259x/45 = 442
x = 76.7953668
x = 76.80°
4x - 142 = 165.18°
x/5 = 15.36°
5x/9 + 60 = 102.66°
If we let x and y represent length and width, respectively, then we can write equations according to the problem statement.
.. x = y +2
.. xy = 3(2(x +y)) -1
This can be solved a variety of ways. I find a graphing calculator provides an easy solution: (x, y) = (13, 11).
The length of the rectangle is 13 inches.
The width of the rectangle is 11 inches.
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Just so you're aware, the problem statement is nonsensical. You cannot compare perimeter (inches) to area (square inches). You can compare their numerical values, but the units are different, so there is no direct comparison.