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barxatty [35]
3 years ago
11

50 POINTS Vanessa has 6 dimes and 2 pennies. Joachim has 1 dollar, 3 dimes, and 5 pennies. Jimmy has 5 dollars and 7 pennies. Th

ey want to put their money together to buy a game that costs $8.00. Do they have enough money to buy the game? If not, how much more money do they need? SHOW WORK
Mathematics
2 answers:
yKpoI14uk [10]3 years ago
7 0

Answer:they need more money

Step-by-step explanation: they need 96 more cents

Yakvenalex [24]3 years ago
3 0

Vanessa: a dime = 10 cents = 0.10

A penny = 1 cent = 0.01

6 x 0.10 = 0.60

2 x 0.01 = 0.02

Total = 0.60 + 0.02 = 0.62

Joachim : a dollar = 1.00

3 x 0.10 = 0.30

5 x 0.01 = 0.05

Total = 1.00 + 0.30 + 0.05 = 1.35

Jimmy: total = 5.00 + 0.07 = 5.07

Total of all 3: 0.62 + 1.35 + 5.07 = $7.04

This is less than $8 so they don’t have enough.

They need: 8.00 - 7.04 = $0.96 more

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Josh mows grass to earn extra money. He charges $25.00 for each lawn. He mows at least 5 yards each week; but not more than 20 y
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Answer:

Let

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125  ≤  f(x)  ≤ 500

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3 years ago
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ss7ja [257]

Answer:

Looks good to me

Step-by-step explanation:

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3 years ago
Adam has 10 blocks numbered 1 through 10. Which describes the probability of randomly choosing a block that has an even number?
Licemer1 [7]

Answer:

\dfrac{1}{2}

Step-by-step explanation:

Given that:

10 number of blocks which have numbers from 1 through 10.

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Probability of randomly choosing a block that has an even number.

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The given set of numbers is: {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}

There are a total of 5 Even numbers are {2, 4, 6, 8, 10}.

And There are a total of 5 Odd number are {1, 3, 5, 7, 9}.

Formula for probability of an event <em>E</em> can be observed as:

P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}

Here, Event <em>E </em>is randomly choosing an even number.

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Total number of cases = 10

Therefore, the required probability is:

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