3 ( 2t + 5 ) = 5 t + 25
3 * 2 t + 3 * 5 = 5 t + 25
6 t + 15 = 5 t + 25
6t - 5t = 25 - 15
t = 10
Hope this helps!
Answer:
<u>Given triangle:</u>
- ΔXYZ
- X(-1,2), Y(2,1), Z(-1, -2)
<u>D₀.₅(ΔXYZ) results in:</u>
- (x, y) → (0.5x, 0.5y)
- X'(-0.5, 1), Y'(1, 0.5), Z(-0.5, -1)
Answer:
0.101
Step-by-step explanation:
Given that :
Standard deviation, s = 0.2
Sample variance, s² = 0.0653
Sample size, n = 10
Population variance = σ² = 0.04
We use the Chi square distribution :
(n - 1)s² / σ²
For P(s² ≥ 0.065)
(n - 1)s² / σ² = (10 - 1)*0.0653 / 0.04
(n - 1)s² / σ² = 0.585 / 0.04 = 14.625
P(s² ≥ 14.625) = 0.101 ( chi squee calculator).
Answer:
3 can
Step-by-step explanation:
there
Answer:
280000lb
Step-by-step explanation:
In this question, we shall be calculating the amount of carbon iv oxide prevented from entering the atmosphere.
Generally we know that 1kwh produces 1.37 lbs of Carbon iv oxide in the atmosphere
Now, using a 100 watt light bulb daily for 8 hours, for a year, the amount of Carbon iv oxide produced will be;
100 * 1.37 * 8 * 365 = 40040 lb
Using a 30 watt CFL for 8hrs/ day for a year, we have;
30 * 1.37 * 8 * 365 = 120012 lb
Now calculating the amount of CO2 prevented, we have 40040 - 120012 = 280028 lb = 280000 after rounding up