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2 years ago

12

Which of the following cannot be the side lengths of a triangle?

1 answer:

mixer [17]2 years ago

4 0

To actually form a triangle, the two SMALLEST sides, have to be bigger than the BIGGEST number, when added together.

A.) Can be a triangle
B.)Can be a triangle
C.)Can be a triangle
D.)Can't be a triangle

2+10=12, and 12 is not bigger than 20.

Thus, D, is your answer.

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5 times a number n verbal expression

NNADVOKAT [17]

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math cant be non verbal

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What is x-2y=1, solve for y

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2 years ago

Why is (x-3) NOT a factor of x3+2x2-5x-6

ivolga24 [154]

As the expression is not equal to zero on x=3, x-3 is not a factor of given expression

Step-by-step explanation:

Given expression is:

$x^3+2x^2-5x-6$

We have to check if x-3 is a factor of given expression

In order for x-3 to be a factor of expression, we have to put x-3 = 0 => x=3 in expression.

If the expression is zero at x=3 then x-3 is a factor of expression otherwise not.

So putting x=333 in expression

$=(3)^3+2(3)^2-5(3)-6\\= 27+2(9) - 15-6\\= 27+18-15-6\\= 45-21\\=24 \neq 0$

As the expression is not equal to zero on x=3, x-3 is not a factor of given expression

Keywords: Polynomials, expressions

Learn more about polynomials at:

#LearnwithBrainly

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3 years ago

Find the volume of the compound shape.

jeyben [28]

<h3>Given:</h3>

Hemisphere ×2 or sphere
Cylinder

<h3>Solution:</h3><h3>Volume of the sphere:</h3>

$v = \frac{4}{3} \pi {r}^{3}$

$v = \frac{4}{3} \times \pi \times {2}^{3}$

$v = 33.51 \: {m}^{3}$

<h3>Volume of the cylinder:</h3>

$v = \pi {r}^{2} h$

$v = \pi \times {2}^{2} \times 6$

$v = 75.40 \: {m}^{3}$

<h3>Total volume:</h3>

$v = 75.40 + 33.51$

$v = 108.91 \: {m}^{3}$

<u>Hence</u><u>,</u><u> </u><u>the</u><u> </u><u>volume</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>given</u><u> </u><u>compound</u><u> </u><u>shape</u><u> </u><u>is</u><u> </u><u>108.91</u><u> </u><u>cubic</u><u> </u><u>meters</u><u>.</u>

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1 year ago

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What is the value of tan(theta)?

Elodia [21]

Answer:The tangent function is negative in the second and fourth quadrants. To find the second solution, subtract the reference angle from

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Step-by-step explanation:

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