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Shkiper50 [21]
3 years ago
14

The latitude value of Toronto is 43.70 degrees, and the longitude value is 79.40 degrees. The latitude value of Melbourne is -37

.81 degrees, and the longitude value is 144.96 degrees. The two cities are degrees apart in latitude. The two cities are degrees apart in longitude.
Mathematics
1 answer:
Aneli [31]3 years ago
3 0
I'm hazarding a guess it's 224.36
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Ratio of nickels t quarters in a dollar
egoroff_w [7]
Since the nickels are first and there are (1.00 /.05= 20) 20 nickels in a dollar the first number is 20 then next is quarters and there is (1.00 / .25= 4) 4 quarters in a dollar so the second number is 4 so now u have to simplify if you were told to 
the number 20 can be divided by 4 and the answer is 5 the number 4 is next divide by 4 and is 1 so the whole answer is 5 to 1 or 5:1<span>
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8 0
3 years ago
PLease help me ,really need help with explanation​
mylen [45]

a)

Check the picture below.

b)

volume wise, we know the smaller pyramid is 1/8 th of the whole pyramid, so the volume of the whole pyramid must be 8/8 th.

Now, if we take off 1/8 th of the volume of whole pyramid, what the whole pyramid is left with is 7/8 th of its total volume, and that 7/8 th is the truncated part, because the 1/8 we chopped off from it, is the volume of the tiny pyramid atop.

Now, what's the ratio of the tiny pyramid to the truncated bottom?

\stackrel{\textit{\Large Volumes}}{\cfrac{\textit{small pyramid}}{\textit{frustum}}\implies \cfrac{~~\frac{1}{8}whole ~~}{\frac{7}{8}whole}}\implies \cfrac{~~\frac{1}{8} ~~}{\frac{7}{8}}\implies \cfrac{1}{8}\cdot \cfrac{8}{7}\implies \cfrac{1}{7}

3 0
2 years ago
13. What is the value of x?
Scilla [17]

9514 1404 393

Answer:

  B.  50

Step-by-step explanation:

The alternate interior angles at transversal t across parallel lines AB and CD will be congruent.

  2x +40 = x +90

  x = 50 . . . . . . . . . . . subtract x+40

The value of x is 50.

_____

<em>Check</em>

2x+40 = 2×50 +40 = 140

x+90 = 50 +90 = 140 . . . . so the obtuse angles are congruent, as they should be

___

<em>Additional comment</em>

The lines AB and CD are not shown as being parallel. We have to assume they are, or we cannot work the problem.

5 0
3 years ago
Graph the system of linear inequalities, please explain the process in solving this problem so I know how to do ones similar to
astra-53 [7]

Answer:

See attached. (Both inequalities graph to the same region.)

Step-by-step explanation:

To graph an inequality, you first replace the inequality symbol by an equal sign. Then you graph the line (or curve) described by the equation. If the inequality symbol includes the "or equal to" case, then the line (or curve) is solid and is part of the solution set. If not, then the line (or curve) is dashed and is <em>not part of the solution set</em>.

Here, the line x+y=5, will bound the solution set, but is not part of it.

Note that the line -x -y = -5 (from the second inequality) is the same ilne.

_____

After you have graphed the boundary of the solution region, you need to determine which side of the boundary has the solutions. I find it easy to do this by locating an x- or y-term with a positive coefficient and seeing which side of the inequality symbol that lies on. Here, both the x-term and the y-term lie on the "is greater than" side of the symbol, so the half-plane is shaded above and to the right of the line, where x- and y-values are greater than they are on the line.

In the second inequality, you can multiply the whole thing by -1 to get

... x + y > 5 . . . . same as the first inequality

or you can add (x+y) to both sides to get

... 0 < -5 +x +y

Once again, the x- and y-values that satisfy this are greater than those that are on the boundary line.

_____

The graph seems to show only one equation. Both are there, but the dashed blue line sits on top of the dashed red line, so you can't see it. The purple shading indicates both red and blue shading in the same area.

===== =====

Of course you graph the boundary line the way you would any linear equation. In this form, it is not too difficult to see that both the x- and y-intercepts are 5. (When x=0, y=5; and when y=0, x=5 for the boundary line's equation x+y=5.) Draw the dotted line through these intercept points, add shading above, and you have your graph.

6 0
3 years ago
Write the equation of a line that is perpendicular to the given line and that passes through the given point.
poizon [28]

Answer: y=-3x+29

Step-by-step explanation:

First put in y-intercept form to find the slope

4x-12y=2\\-12y=-4x+2\\y=\frac{1}{3} x-\frac{1}{6}

Slope of the 1st equation is 1/3-  the slope of the line perpendicular is the opposite reciprocal, so in the case it is -3

Use the point and the new slope to write the new equation in point slope format

y-y_{1} =m(x-x_{1} )\\y-(-1)=-3(x-10)\\y+1=-3x+30\\y=-3x+29

8 0
3 years ago
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