So subsitue and try so
f(g(x))=2(7x+1)+2
g(f(x))=7(2x+2)+1
multiply them out
f(g(x))=2(7x+1)+2=14x+2+2=14x+4
g(f(x))=7(2x+2)+1=14x+14+1=14x+15
14x+15>14x+4
therefor
g(f(x))>f(g(x))
the answer is D g(f(x)) produces the greatest output
An angle of 180° is flat, so it can't be an exterior angle of a triangle.
your answer is:
never true
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Answer:
Lin has 11 acorns ⇒ answer D
He subtract 4 from 7 instead of add 4 to 7
Step-by-step explanation:
- Lin has 4 pinecones and some acorns
- She has 7 fewer pinecones than acorns
- The meaning of 7 fewer pinecones than acorns is the number of the
pinecones is less than the number of acorns by 7
∵ She has 4 pinecones
∵ She has 7 fewer pinecones than acorns
- The number of pine cones is less than the number of acorns by 7
∴ 4 = number of acorns - 7
- Add 7 to both sides
∴ 11 = number of acorns
*<em> Lin has 11 acorns</em>
- Tom choose answer A which is 3
- He made a mistake in the equation
- He put ⇒ number of the acorns = 7 - 4 not 7 + 4
∴ number of acorns = 3
* <em>He subtract 4 from 7 instead of add 4 to 7</em>
I think the question has to do with the number of students who are attending the university but is neither an undergraduate nor living off-campus. To help us solve this problem, we use the Venn diagram as shown in the picture. The intersection of the 2 circles would be 3 students. The students in the 'students living off-campus' circle would be 9 - 2 = 6, while the undergraduate students would be 36-3 = 33. The total number of students inside all the circles and outside the circles should sum up to 60 students.
6 + 3 + 33 + x = 60
x = 60 - 6 - 3 - 3
x = 18 students
Therefore, there are 18 students who are neither an undergraduate nor living off-campus