Let X be the number of lightning strikes in a year at the top of particular mountain.
X follows Poisson distribution with mean μ = 3.8
We have to find here the probability that in randomly selected year the number of lightning strikes is 0
The Poisson probability is given by,
P(X=k) =
Here we have X=0, mean =3.8
Hence probability that X=0 is given by
P(X=0) =
P(X=0) =
P(X=0) = 0.0224
The probability that in a randomly selected year, the number of lightning strikes is 0 is 0.0224
Hey There Remone,
<span>Order the fraction from least to greatest 1/4,1/6,1/5
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he saves $860 per month
calculate each of his outgoings
rent = × $3600 = = $900
food = × $3600 = = $1440
activities = × $3600 = = $400
savings = $3600 - ( 900 + 1440 + 400 ) = $860
Answer:
16
Step-by-step explanation:
I think it is d=5 because when you add them all up and divide by 5 it is 5