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3 years ago

Write an standard form of: slope=-10/3 , y-intercept=5

Mathematics

1 answer:

rodikova [14]3 years ago

3 0

Answer:

Input work is the work done on a machine as the input force acts through the input distance. This is in contrast to output work which is a force that is applied by the body or system to something else. Output work is the work done by a machine as the output force acts through the output distance.Jan 15, 2020 bshdggxgxgx xysfshsfsvsydvfnshdgdbdycbd dgd dh dgx dgx d

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Please help me:(<br> tysm

Rzqust [24]

Answer:

Step-by-step explanation:

6 0

3 years ago

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Hillary is making a blanket for her mom. Three fourths of the blanket is green and the rest is yellow. Two thirds of the yellow

Leviafan [203]

Answer:

1/6

Step-by-step explanation:

Hillary is making a blanket for her mom.

Let the total blanket = 1

Three-fourths of the blanket is green and the rest is yellow.

The fraction for the rest(yellow portion) = 1 - 3/4

The Lowest Common Denominator is 4

Hence,

4 - 3 /4 = 1/4

Two-thirds of the yellow part has her name on it.

The fraction of the blanket that will have her name on it is calculated as

2/3 of 1 /4

= 2/3 × 1/4

= 1/6

4 0

3 years ago

What is the solution to the equation 1/x = x+3/2x^2

dusya [7]

D. x = 3 because 3+3 is 6 and that is over 2*3^2 which is 2*9 which means it is 6/18 then you divide both the numerator and denominator by 6 and that =1/3.

4 0

4 years ago

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The graph of an inverse trigonometric function passes through the point (1, pi/2). Which of the following could be the equation

rodikova [14]

Answer: C) $y=sin^-1 x$

Step-by-step explanation:

Since, the graph of an inverse trigonometric function will pass through the point $(1,\frac{\pi}{2})$ ,

If this point satisfies the function,

For the function $y=cos^{-1} x$

If x = 1

$y=cos^{-1}1=0$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=cos^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=cot^{-1}x$

If x = 1

$y=cot^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cot^{-1}x$ ,

⇒ The graph of $y=cot^{-1}x$ is not passing through the point $(1,\frac{\pi}{2})$

For the function $y=sin^{-1} x$

If x = 1

$y=sin^{-1}1=\frac{\pi}{2}$

Thus, $(1,\frac{\pi}{2})$ is satisfying function $y=sin^{-1} x$ ,

⇒ The graph of $y=sin^{-1} x$ is passing through the point $(1,\frac{\pi}{2})$ .

For the function $y=tan^{-1}x$

If x = 1

$y=tan^{-1}1=\frac{\pi}{4}$

Thus, $(1,\frac{\pi}{2})$ is not satisfying function $y=cos^{-1} x$ ,

⇒ The graph of $y=tan^{-1} x$ is not passing through the point $(1,\frac{\pi}{2})$ .

Hence, Option C is correct.

3 0

3 years ago

1. 7(6-(-4))<br> What is this I don’t know

Marina CMI [18]

So you would start with removing the parentheses so 6- - 4 would be 6+4 because the double negative and then that would be 10 so 7 times 10 so your answer is 70

5 0

3 years ago

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