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marishachu [46]
2 years ago
13

!!!! I'LL GIVE BRAINLIEST !!!!! PLS HELP THIS IS A TEST !!!

Mathematics
1 answer:
vodomira [7]2 years ago
4 0

Step-by-step explanation:

The answer is (SAS) Rule

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Will give brainliest! Need help asap!
scZoUnD [109]

Let's write f(x)=4x-1, g(x)=-3x+5

We see f(.8)=2.2, g(.8)=2.6    close, with g a bit bigger

then f(.9)=2.6, g(.9)=2.3      also close, with f a bit bigger

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3 0
3 years ago
Can y = sin(t2) be a solution on an interval containing t = 0 of an equation y + p(t) y + q(t) y = 0 with continuous coefficient
JulsSmile [24]

Answer:

Step-by-step explanation:

y = sin(t^2)

y' = 2tcos(t^2)

y'' = 2cos(t^2) - 4t^2sin(t^2)

so the equation become

2cos(t^2) - 4t^2sin(t^2) + p(t)(2tcos(t^2)) + q(t)sin(t^2) = 0

when t=0, above eqution is 2. That is, there does not exist the solution. so y can not be a solution on I containing t=0.

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