To me, the Answer to this problem is A. Crossing Gates.
Answer:
D. f(x) exist for all real numbers where x ≤ -1 or x ≥ 1
Explanation:
You can't divide by 0 and
You can't have a negative squareroot.
So solve for when x=0 for the denominator,
and when is x<0 for the squareroot.
I think it’s better for him to ask you but there is nothing wrong with asking him, hope ur prom will be fantastic!