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3 years ago

PLEASE HELP ASAP!!!!! WILL GIVE BRAINLIEST TO FIRST CORRECT ANSWER!!!!!

Mathematics

1 answer:

Stells [14]3 years ago

4 0

The answer to this question is the second graph.

Hope this helps

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Which algebraic represent 15 less than x divided by 9

polet [3.4K]

X/9 - 15
X divided ( / ) by 9 minus ( - ) 9

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3 years ago

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Solve for x and y y+2x=2 y=-4x+10

Katena32 [7]

Answer:

x=4 and y=(-6)

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation.

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3 years ago

23 order Pepsi and 15 order mountain dew . How many more orders have there been for Pepsi then mountain dew

Inessa [10]

There 8 more orders of Pepsi then Mountain dew.

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WHAT IS X³-27 SIMPLIFIED

Eduardwww [97]

Answer:

It is (x - 3)³ - 9x(3 - x)

Step-by-step explanation:

Express 27 in terms of cubes, 27 = 3³:

$= {x}^{3} - {3}^{3}$

From trinomial expansion:

${(x - y)}^{3} = (x - y)(x - y)(x - y) \\$

open first two brackets to get a quadratic equation:

${(x - y)}^{3} = ( {x}^{2} - 2xy + {y}^{2} )(x - y)$

expand further:

${(x - y)}^{3} = {x}^{3} - y {x}^{2} - 2y {x}^{2} + 2x {y}^{2} + x {y}^{2} - {y}^{3} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3x {y}^{2} - 3y {x}^{2} \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3xy(y - x) \\ \\ { \boxed{( {x}^{3} - {y}^{3} ) = {(x - y)}^{3} - 3xy(y - x)}}$

take y to be 3, then substitute:

$( {x}^{3} - 3^3) = {(x - 3)}^{3} - 9x(3 - x)$

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3 years ago

Find a recursive formula for the sequence: 1, -1, -7, -25

Mumz [18]

<h3>Answer:</h3>

$a_n=3a_{n-1}-4$

<h3>Step-by-step explanation:</h3>

Try the answers

You can try the answers to see what works. You can expect all of the choices to match the first two terms, so try some farther down. Let's see if we can get -25 from -7.

a) 3*(-7) -4 = -21 -4 = -25 . . . . this one works

b) -7 -2 = -9 . . . . ≠ -25

c) -3(-7) +2 = 21 +2 = 23 . . . . ≠ -25

d) -2(-7) +1 = 14 +1 = 15 . . . . ≠ -25

The formula that works is the first one.

_____

Derive it

All these formulas depend on the previous term only, so we can write equations that show the required relationships. Let the unknown coefficients in our recursion formula be p and q, as in ...

$a_n=p\cdot a_{n-1}+q$

Then, to get the second term from the first, we have

... 1·p +q = -1

And to get the third term from the second, we have

... -1·p +q = -7

Subtracting the second equation from the first gives ...

... 2p = 6

... p = 3 . . . . . . . this is sufficient to identify the first answer as correct

We can find q from the first equation.

... q = -1 -p = -1 -3 = -4

So, our recursion relation is ...

$a_n=3a_{n-1}-4$

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3 years ago