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Hitman42 [59]
3 years ago
10

Tristen is packing lunch boxes for the school trip. Each lunch box consists of 1 sandwich, 1 fruit, and 1 drink. Tristen can cho

ose from 3 types of sandwiches, 4 types of fruit, and 2 types of drinks. How many different lunch boxes can Tristen pack?
(question: is this a combination or a permutation?

(please answer legitimately I will give you the brainliest)
Mathematics
1 answer:
Lerok [7]3 years ago
6 0

Step-by-step explanation:

3*4*2=24

Even if he doesn't use them all, he has 24 choices.

These kind of problems are permutation type problem. Order is not critical. Imagine yourself preparing such a meal. You have choices to be made in Sandwiches, fruits and drinks. It does not matter which order you set up the lunch box. It only matters that you chose.

You can't leave one out, nor does the problem allow you to trade (say) 2 drinks for one fruit.

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We would like to create a confidence interval.
Vlada [557]

Answer:

c.A 90% confidence level and a sample size of 300 subjects.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level 1-\alpha, we have the confidence interval with a margin of error of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

In this problem

The proportions are the same for all the options, so we are going to write our margins of error as functions of \sqrt{\pi(1-\pi)}

So

a.A 99% confidence level and a sample size of 50 subjects.

n = 50

99% confidence interval

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.3642\sqrt{\pi(1-\pi)}

b.A 90% confidence level and a sample size of 50 subjects.

n = 50

90% confidence interval

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{50}}\sqrt{\pi(1-\pi)} = 0.2623\sqrt{\pi(1-\pi)}

c.A 90% confidence level and a sample size of 300 subjects.

n = 300

90% confidence interval

So \alpha = 0.1, z is the value of Z that has a pvalue of 1 - \frac{0.1}{2} = 0.95, so Z = 1.645.

The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{1.645}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.0950\sqrt{\pi(1-\pi)}

This produces smallest margin of error.

d.A 99% confidence level and a sample size of 300 subjects.

n = 300

99% confidence interval

So \alpha = 0.01, z is the value of Z that has a pvalue of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

The margin of error is

M = z\sqrt{\frac{\pi(1-\pi)}{n}} = \frac{2.575}{\sqrt{300}}\sqrt{\pi(1-\pi)} = 0.1487\sqrt{\pi(1-\pi)}

6 0
3 years ago
The dot plot below shows the number of cakes 31 chefs made in a week: Dot plot labeled Number of Cakes Made shows 4 dots over 1,
Paraphin [41]
The median, because the data is not symmetric and there are outliers is the data is not symmetric and there are outliers.

The median of the data set is 8 cakes, while the average is 7.5.

However, 21 of the 31 chefs, or roughly 2/3, made 8 or more cakes. This makes the median a better center for this data, since the data is clearly skewed. The four chefs that made 1 cake each brings the average down, skewing the mean and making the median a better representation of the data. 
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3 years ago
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Svetach [21]

Answer: a. 55

Step-by-step explanation:

The formula to find the geometeric mean between two numbers a and b is given by :-

G.M. =\sqrt{ab}

The given numbers are : 275 and 11

The geometric mean of 275 and 11 is given by :-

G.M.=\sqrt{275\times11}\\\\\Rightarrow\ G.M. =\sqrt{3025}\\\\\Rightarrow\ G.M.=\sqrt{55\times55}\\\\\Rightarrow\ G.M.=\sqrt{55^2}\\\\\Rightarrow\ G.M.=55

Hence, the geometric mean of 275 and 11 is 55.

So , the correct option is a. 55 .

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iragen [17]

Answer:

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Step-by-step explanation:

I think this is right

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The diameter is 18.8 feet
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