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2 years ago

Starting billions of years ago, in what way did algae change the atmosphere of

Biology

2 answers:

docker41 [41]2 years ago

6 0

Answer:carbon dioxide was converted to oxygen

Explanation:

Jobisdone [24]2 years ago

5 0

In 1990 it change our atmosphere and it started growing on trees and other thing to

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Which process must occur before mitosis and meiosis can occur?

STALIN [3.7K]

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

Hello!

✧･ﾟ: *✧･ﾟ:* *:･ﾟ✧*:･ﾟ✧

❖ Before mitosis and meiosis occur, DNA replication has to occur. DNA replication is when another copy is made of the DNA and in mitosis and meiosis, you need the replicated DNA for the sister chromatids.

~ ʜᴏᴘᴇ ᴛʜɪꜱ ʜᴇʟᴘꜱ! :) ♡

~ ᴄʟᴏᴜᴛᴀɴꜱᴡᴇʀꜱ

4 0

2 years ago

The location of the neritic zone is determined by ______

EleoNora [17]

The answer is D.
hope it helps:)

4 0

2 years ago

Read 2 more answers

How old would you be on Mercury if our 15?

mamaluj [8]

Answer:

you would be probably 68

Explanation:

8 0

2 years ago

Glucose labeled with 14C in C-3 and C-4 is completely converted to acetyl-CoA via glycolysis and the pyruvate dehydrogenase comp

Morgarella [4.7K]

Answer:

The correct answer is option d.

Explanation:

The production of Acetyl-CoA takes place by the dissociation of both carbohydrates and lipids in the process of glycolysis and beta-oxidation. It then moves into the TCA cycle in the mitochondria and combines with oxaloacetate to give rise to citrate.

In the given case, no labeling will be found in the acetyl-CoA. The labeled C3 and C4 carbon of glucose signify the carboxyl carbon of pyruvate. In the succeeding reactions of the transformation of pyruvate to acetyl-CoA, the carboxyl carbon gets lost in the form of carbon dioxide. Thus, acetyl-CoA does not comprise any labeled C3 and C4 of glucose.

5 0

3 years ago

Suppose that an adult black bear adds 50 pounds of fat in order to survive while hibernating through the winter. how much glycog

NemiM [27]

Answer: The correct answer would be 112.5 pounds

Explanation:

Let us first covert the pound into grams. We know that 1 pound is equal to 453.59 grams.

Thus, 50 pound of fat = 50 x 453.59 = 22,679.5 grams.

We know that, 1 gram of fat releases 9 Kcal of energy. Thus, total energy produced by 22679.5 grams = 9 x 22679.5 = 204,115.5 Kcal

Glycogen is carbohydrate thus, it will produce 4 Kcal of energy per gram.

Thus, 4 x C = 204,115.5 (where C is the grams of glycogen)

⇒ C = $\frac{204115.5}{4}$

⇒ C = 51,028.875 grams

Using 1 pound = 453.59 grams, we con convert 51,028.875 grams into pounds:

453.59 = 1

1 = $\frac{1}{453.59}$

51,028.875 = $\frac{1}{453.59} x 51028.875$

= 112.5 pounds

Thus, 112.5 pound of glycogen would be needed to produce the same amount of energy as produced by 50 pounds of fat.

8 0

2 years ago