Answer:
A) AUG GAG GGU
B) N-MET-GLU-GLY-HIS
C) 10 amino acids
D) The stop codon here is UAA, instead of UAG. If a tryptophane residue is added where the stop codon is, the GEN polypeptide would be longer
Explanation:
First we must obtain the the complementary chain or mRNA
A) AUG start codon is complementary to DNA TAC triplet, and GAG is complementary to CTC, and GGU to CCA (running from left to right towards 5'DNA direction (AAGCGGATACCTCCCAGTAGATGCTCCGGGGCTAGTGATTTCGAAC-5)
B) TAC corresponds to Methionine, GAG to Glutamate, GGU to Glycine, and CAU to Histidine
C) UAA is the stop codon, that is complementary where the DNA triplet is ATT. From AUG to UAA, we can have 10 amino acids transcribed
D) If a trp is included where the stop codon is UAA, then the mRNA would be longer with a consequent traduction of a longer GEN polypeptide
Answer and Explanation:
As I don't have access to live butterflies, the control group would be clay models that do not exhibit warning coloration, e.g. beige / white / brown. In contrast, the experimental group would be the clay models that exhibir a strong warning coloration such as color orange / red.
After preparing the clay 'prey', I would locate them in specific places outside where birds are able to detect them. Moreover, I would use a webcam to monitor the recurrence of birds in the area.
1st experiment: Test whether birds approach the prey that exhibits both warning coloration (experimental group) and dull coloration (control group). Then, record the minutes they spent wandering near the prey.
2nd experiment: Test wheter birds feed on the prey that exhibits both warning coloration (experimental group) and dull coloration (control group). Record time.
Carry out statistical analyses.
Present results and discuss.
Answer:
Small Shrubs
Explanation:
They Give off energy that makes them dominate the coniferous forest biome
